c++ - 当使用按值调用时，实际参数值被压入堆栈。通过引用调用呢？

Question

当使用按值调用时，实际参数值被压入堆栈。通过引用调用呢？什么被压入调用堆栈？

编辑:

很高兴知道 java 从来不使用引用调用。在 C++ 中怎么样。我将标签从 java 更改为 c++。抱歉造成混淆。

Answer 1

Java 中没有引用调用。一切都是按值调用。

来自 Is Java "pass-by-reference" or "pass-by-value"?

Java is always pass-by-value. The difficult thing can be to understand that Java passes objects as references passed by value.

来自 http://www.javaworld.com/javaworld/javaqa/2000-05/03-qa-0526-pass.html

Java does manipulate objects by reference, and all object variables are references. However, Java doesn't pass method arguments by reference; it passes them by value.

参见 this answer进一步解释。

What about call by reference? What is pushed onto the call stack?

然后引用被压入操作数栈。