我有点困惑如何将我的 SDL_Surface 传递给我的函数,以便我可以在 SDL 中设置我的屏幕。
这是我的错误:
No operator "=" matches these operands
我的功能是这样的:
void SDL_Start(SDL_Surface screen){
Uint32 videoflags = SDL_SWSURFACE | SDL_DOUBLEBUF | SDL_ANYFORMAT;// | SDL_FULLSCREEN;
// Initialize the SDL library
if ( SDL_Init(SDL_INIT_VIDEO) < 0 ) {
fprintf(stderr, "Couldn't initialize SDL: %s\n",
SDL_GetError());
exit(500);
}
//get player's screen info
const SDL_VideoInfo* myScreen = SDL_GetVideoInfo();
//SDL screen
int reso_x = myScreen->current_w;
int reso_y = myScreen->current_h;
Uint8 video_bpp = 32;
//setup Screen [Error on the line below]
screen = SDL_SetVideoMode(reso_x, reso_y, video_bpp, videoflags|SDL_FULLSCREEN);
}
这个函数在我的主函数中是这样调用的:
SDL_Surface *screen;
SDL_Start(*screen);
知道错误是什么吗?
最佳答案
SDL_SetVideoMode
返回一个 SDL_Surface*
(指针类型),但您将其分配给一个 SDL_Surface
(非指针)。
编辑:这可能就是您想要的。返回指向新表面的指针。
SDL_Surface* SDL_Start() {
Uint32 videoflags = SDL_SWSURFACE | SDL_DOUBLEBUF | SDL_ANYFORMAT;// | SDL_FULLSCREEN;
// Initialize the SDL library
if ( SDL_Init(SDL_INIT_VIDEO) < 0 ) {
fprintf(stderr, "Couldn't initialize SDL: %s\n",
SDL_GetError());
exit(500);
}
//get player's screen info
const SDL_VideoInfo* myScreen = SDL_GetVideoInfo();
//SDL screen
int reso_x = myScreen->current_w;
int reso_y = myScreen->current_h;
Uint8 video_bpp = 32;
//setup Screen [Error on the line below]
return SDL_SetVideoMode(reso_x, reso_y, video_bpp, videoflags|SDL_FULLSCREEN);
}
// ...
SDL_Surface *screen = SDL_Start();
关于c++ - 将 SDL 表面传递给函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13151175/