c++ - 从 boost::property_tree::ptree::iterator 获取 ptree

标签 c++ xml boost tree boost-propertytree

我有一段代码可以遍历 boost 属性树 (XML)。
我需要当前节点的 ptree,而不是节点的子节点。

更新

xml树

<node id="A.html">
    <subnode> child A1 </subnode>
    <subnode> child A2 </subnode>
</node>

<node id="B.html">
    <subnode> child B1 </subnode>
    <subnode> child B2 </subnode>
</node>

迭代代码

void parse_tree(ptree& pt, std::string key)
{
    string nkey;
    if (!key.empty())
    nkey = key + ".";

    ptree::const_iterator end = pt.end();
    for(ptree::iterator it = pt.begin(); it != end; ++it){

        //if the node's id is a .html filname, save the node to file
        string id = it->second.get("<xmlattr>.id","");

        if(id.find("B.html") != std::string::npos){  //Let's just test for "B.html"
            write_xml("test.html", pt);           //saves entire tree
            write_xml("test.html", it->second);   //saves only children of the node
        }

        parse_tree(it->second, nkey + it->first); //recursion
    }
}

使用 write_xml("test.html", pt) 的结果

(我们得到整棵树,我们只想要节点)

<node id="A.html">
    <subnode> child A1 </subnode>
    <subnode> child A2 </subnode>
</node>
<node id="B.html">
    <subnode> child B1 </subnode>
    <subnode> child B2 </subnode>
</node>

使用 write_xml("test.html", it->second) 的结果

(我们没有父节点..只有子节点)

<subnode> child B1 </subnode>
<subnode> child B2 </subnode>

想要的结果

(我们想要节点,它是子节点,..就像这样)

<node id="B.html">
    <subnode> child B1 </subnode>
    <subnode> child B2 </subnode>
</node>

最佳答案

更新 2

为回应评论/更新的问题而重写。

有两种方法。

  1. 您可以使用未记录的函数 write_xml_element 编写单个元素(使用键作为元素名称):

        // write the single element: (undocumented API)
        boost::property_tree::xml_parser::write_xml_element(
                std::cout, it->first, it->second,
                0, settings
            );
    
  2. 或者您可以使用单个 child 创建一个新的ptree对象

        ptree tmp;
        tmp.add_child(it->first, it->second);
        write_xml(std::cout, tmp, settings);
    

Live On Coliru

#include <boost/property_tree/ptree.hpp>
#include <boost/property_tree/xml_parser.hpp>

#include <fstream>
#include <iostream>

using namespace boost::property_tree;


void parse_tree(ptree& pt, std::string key)
{
    std::string nkey;
    auto settings = xml_parser::xml_writer_make_settings<std::string>('\t', 1);

    if (!key.empty()) {
        nkey = key + ".";
    }

    ptree::const_iterator end = pt.end();
    for(ptree::iterator it = pt.begin(); it != end; ++it)
    {
        //if the node's id an .html filname, save the node to file
        std::string id = it->second.get("<xmlattr>.id","");

        if (id.find(key) != std::string::npos) {
            // write the single element: (undocumented API)
            boost::property_tree::xml_parser::write_xml_element(
                    std::cout, it->first, it->second,
                    0, settings
                );

            // or: create a new pt with the single child
            std::cout << "\n==========================\n\n";
            ptree tmp;
            tmp.add_child(it->first, it->second);
            write_xml(std::cout, tmp, settings);
        }

        parse_tree(it->second, nkey + it->first); //recursion
    }
}

int main() {
    ptree pt;
    read_xml("input.txt", pt);

    parse_tree(pt, "B");
}

输出:

<node id="B.html">
    <subnode> child B1 </subnode>
    <subnode> child B2 </subnode>
</node>

==========================

<?xml version="1.0" encoding="utf-8"?>
<node id="B.html">    
    <subnode> child B1 </subnode>
    <subnode> child B2 </subnode>
</node>

关于c++ - 从 boost::property_tree::ptree::iterator 获取 ptree,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28372268/

相关文章:

c++ - "Ends_with"读取输入文件时函数不工作

c++ - 使用 C++ 删除旧文件

php - 如何将多维 PHP 数组转换为 XML?

c++ - 是否可以创建一个容器来保存三种数据类型中的一种,并且可以通过单个界面进行查询?

c++ - 涉及 boost_lock 的链接器错误

c++ - 如何不使用 getter 方法访问动态对象属性?

c++ - Eclipse CDT 适用于

html - 如何从 XMLDocumentContent 对象中提取 $children$html 内容

xml - 格式字符串-删除前导数字

boost - 记录 Boost.Test 测试用例