c++ - 将 std::string 转换为 boost::asio::streambuf

Question

如何将 std::string 转换为 boost::asio::streambuf？ 任何领导表示赞赏。

最初我使用 boost::asio::read_until(pNetworkConnector->getSocket(), response, "\r\n"); 初始化了 boost::asio::streambuf response 并将其转换为底层流，即

boost::asio::streambuf* responsePointer = &response;
iResponseStream.rdbuf(responsePointer);

但现在我像这样使用 curl 直接得到一个 std::string

static size_t WriteCallback(void* contents, size_t size, size_t nmemb, void* userp)
{
    ((std::string*)userp)->append((char*)contents, size * nmemb);
    return size * nmemb;
}

并将其用作

curl_easy_setopt(handle, CURLOPT_WRITEFUNCTION, WriteCallback);
curl_easy_setopt(handle, CURLOPT_WRITEDATA, &readBuffer);

如何将 std::string 转换为 boost::asio::streambuf 或 std::streambuf ？

Answer 1

下面的代码展示了如何在std::string和boost::asio::streambuf之间进行转换，参见online at ideone :

#include <iostream>
#include <boost/asio/streambuf.hpp>
#include <boost/asio/buffer.hpp>

int main()
{
   /* Convert std::string --> boost::asio::streambuf */
   boost::asio::streambuf sbuf;
   std::iostream os(&sbuf);
   std::string message("Teststring");
   os << message;

   /* Convert boost::asio::streambuf --> std::string */
   std::string str((std::istreambuf_iterator<char>(&sbuf)),
                    std::istreambuf_iterator<char>());

   std::cout << str << std::endl;
}