javascript - jslint中的 "unexpected++"错误

Question

那么是的最佳实践是什么？

Jslint 解释说它“增加了困惑”。真的没看出来……

编辑:代码，根据要求:

  var all,l,elements,e;
  all = inElement.getElementsByTagName('*');
  l = all.length;
  elements = [];
  for (e = 0; e < l; (e++))
  {
    if (findIn)
    {
        if (all[e].className.indexOf(className) > 0)
        {
            elements[elements.length] = all[e];
        }
    } else {
        if (all[e].className === className)
        {
            elements[elements.length] = all[e];
        }
    }
  }

Answer 1

长期的最佳实践:按照 jslint 的建议改用 i += 1。

至于为什么它比 ++ 更好，根据 Crockford 的说法:

The increment ++ and decrement -- operators make it possible to write in an extremely terse style. In languages such as C, they made it possible to write one-liners that: for (p = src, q = dest; !*p; p++, q++) *q = *p; Most of the buffer overrun bugs that created terrible security vulnerabilities were due to code like this. In my own practice, I observed that when I used ++ and --, my code tended to be too tight, too tricky, too cryptic. So, as a matter of discipline, I don’t use them any more.

编辑:包含来自 Nope 的评论随着这个答案不断得到关注。