我要重构:
const char* arr =
"The "
"quick "
"brown";
变成类似的东西:
const char* quick = "quick ";
const char* arr =
"The "
quick
"brown";
因为字符串“quick”被用在很多其他地方。理想情况下,我需要能够只使用 const 原始类型来做到这一点,所以没有字符串。执行此操作的最佳方法是什么?
最佳答案
以答案的形式编译评论:
使用宏。
#define QUICK "quick " char const* arr = "The " QUICK "brown";
使用
std:string
。std::string quick = "quick "; std::string arr = std::string("The ") + quick + "brown";
工作代码:
#include <iostream>
#include <string>
#define QUICK "quick "
void test1()
{
char const* arr = "The " QUICK "brown";
std::cout << arr << std::endl;
}
void test2()
{
std::string quick = "quick ";
std::string arr = std::string("The ") + quick + "brown";
std::cout << arr << std::endl;
}
int main()
{
test1();
test2();
}
输出:
The quick brown
The quick brown
关于c++ - 通过连接另一个 char* 来初始化 const char*,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26807775/