除了名字和姓氏之间不允许有空格外，该程序可以正常工作。下面是关于我正在谈论的内容的示例:
有人可以帮我解决这个问题吗？我相信它在 string playerName 中，因为它不接受名字和姓氏之间的空格。
#include "stdafx.h"
#include <iostream>
#include <string>
#include <iomanip>
using namespace std;
// Structure to hold the Player Data
struct Player {
string playerName;
int playerNumber;
int pointsScored;
};
// Function Prototypes
void getPlayerInfo(Player &);
void showInfo(Player[], int);
int getTotalPoints(Player[], int);
void showHighest(Player[], int);
int main(int argc, char *argv[])
{
const int N = 12;
Player players[N];
for (int i = 0; i<N; i++) {
cout << "\nPLAYER #" << i + 1 << "\n";
cout << "---------\n";
getPlayerInfo(players[i]);
}
showInfo(players, N);
int totalPoints = getTotalPoints(players, N);
cout << "TOTAL POINTS: " << totalPoints << "\n";
cout << "The player who scored the most points is :";
showHighest(players, N);
cout << "\n";
system("pause");
return 0;
}
void getPlayerInfo(Player &P) {
cout << "Player Name:";
//cin >> P.playerName; **CHANGED THIS**
cin.ignore(std::numeric_limits<std::streamsize>::max(), ' ');
std::getline(std::cin, P.playerName); **TO THIS**
do {
cout << "Player Number:";
cin >> P.playerNumber;
if (P.playerNumber<0)
cout << "invalid Input\n";
} while (P.playerNumber<0);
do {
cout << "Points Scored:";
cin >> P.pointsScored;
if (P.pointsScored<0)
cout << "invalid Input\n";
} while (P.pointsScored<0);
}
void showInfo(Player P[], int N) {
cout << "\nNAME" << "\t\tNUMBER" << "\t\tPOINTS SCORED" << "\n";
for (int i = 0; i<N; i++)
cout << P[i].playerName << "\t\t" << P[i].playerNumber << "\t\t" << P[i].pointsScored << "\n";
}
int getTotalPoints(Player P[], int N) {
int Points = 0;
for (int i = 0; i<N; i++)
Points += (P[i].pointsScored);
return Points;
}
void showHighest(Player P[], int N) {
int HighestPoint = P[0].pointsScored;
string Name = P[0].playerName;
for (int i = 1; i<N; i++) {
if (HighestPoint<P[i].pointsScored) {
HighestPoint = P[i].pointsScored;
Name = P[i].playerName;
}
}
cout << Name;
}
最佳答案
当 std::cin 使用 operator>> 插入到 std::string 时，它会在空格处停止读取(' ') 个字符。请改用 std::getline。
std::getline(std::cin, P.playerName); //read everything up to '\n'
关于c++ - 带字符间距的字符串，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/33860929/