c++ - 无限模板递归,因为仅使用 gcc 没有 bool 表达式优化

标签 c++ templates gcc sfinae enable-if

我正在研究一个词法施法者。请参阅下面代码中简化的、有问题的部分。该代码使用 clang 和 msvc 编译,但无法使用 gcc 编译。看起来,在 lexicalCast 的 std::enable_if 的第一个参数中gcc 尝试在评估之前评估 bool 表达式的所有操作数,而 clang 和 msvc 进行优化并忽略 LexicalCastable<>:: value 的评估如果std::is_same表达式失败。 我的问题是:

  • 标准是否规定了哪些行为是正确的?
  • 如何解决这个问题才能用 GCC 编译这段代码?

代码:

#include <type_traits>
#include <string>

template<typename From, typename To>
class LexicalCastable;

template<typename To, typename From> typename
    std::enable_if<
           !std::is_same<std::string, To>::value
        && !std::is_same<std::string, From>::value
        && LexicalCastable<From, std::string>::value
        && LexicalCastable<std::string, To>::value,
To>::type lexicalCast(const From &from) {
    return lexicalCast<To>(lexicalCast<std::string>(from));
}

template<typename From, typename To>
class LexicalCastable
{
    template<typename TT>
    static auto test(int)
        -> decltype(lexicalCast<TT>(std::declval<From>()), std::true_type{});

    template<typename>
    static auto test(...)->std::false_type;

public:
    static const bool value = decltype(test<To>(0))::value;
};

static_assert(!LexicalCastable<std::string, std::string>::value, "");

gcc 错误:

prog.cpp: In substitution of ‘template<class TT> static decltype ((lexicalCast<TT>(declval<From>()), std::true_type{})) LexicalCastable<From, To>::test(int) [with TT = std::__cxx11::basic_string<char>]’:
prog.cpp:35:45:   required from ‘const bool LexicalCastable<std::__cxx11::basic_string<char>, std::__cxx11::basic_string<char> >::value’
prog.cpp:19:3:   required by substitution of ‘template<class To, class From> typename std::enable_if<(((((! std::is_constructible<To, From>::value) && (! std::is_same<std::__cxx11::basic_string<char>, To>::value)) && (! std::is_same<std::__cxx11::basic_string<char>, From>::value)) && LexicalCastable<From, std::__cxx11::basic_string<char> >::value) && LexicalCastable<std::__cxx11::basic_string<char>, To>::value), To>::type lexicalCast(const From&) [with To = std::__cxx11::basic_string<char>; From = <missing>]’
prog.cpp:29:30:   required by substitution of ‘template<class TT> static decltype ((lexicalCast<TT>(declval<From>()), std::true_type{})) LexicalCastable<From, To>::test(int) [with TT = std::__cxx11::basic_string<char>]’
prog.cpp:35:45:   required from ‘const bool LexicalCastable<std::__cxx11::basic_string<char>, std::__cxx11::basic_string<char> >::value’
prog.cpp:19:3:   required by substitution of ‘template<class To, class From> typename std::enable_if<(((((! std::is_constructible<To, From>::value) && (! std::is_same<std::__cxx11::basic_string<char>, To>::value)) && (! std::is_same<std::__cxx11::basic_string<char>, From>::value)) && LexicalCastable<From, std::__cxx11::basic_string<char> >::value) && LexicalCastable<std::__cxx11::basic_string<char>, To>::value), To>::type lexicalCast(const From&) [with To = std::__cxx11::basic_string<char>; From = <missing>]’
prog.cpp:29:30:   [ skipping 889 instantiation contexts, use -ftemplate-backtrace-limit=0 to disable ]
prog.cpp:35:45:   required from ‘const bool LexicalCastable<std::__cxx11::basic_string<char>, std::__cxx11::basic_string<char> >::value’
prog.cpp:19:3:   required by substitution of ‘template<class To, class From> typename std::enable_if<(((((! std::is_constructible<To, From>::value) && (! std::is_same<std::__cxx11::basic_string<char>, To>::value)) && (! std::is_same<std::__cxx11::basic_string<char>, From>::value)) && LexicalCastable<From, std::__cxx11::basic_string<char> >::value) && LexicalCastable<std::__cxx11::basic_string<char>, To>::value), To>::type lexicalCast(const From&) [with To = std::__cxx11::basic_string<char>; From = <missing>]’
prog.cpp:29:30:   required by substitution of ‘template<class TT> static decltype ((lexicalCast<TT>(declval<From>()), std::true_type{})) LexicalCastable<From, To>::test(int) [with TT = std::__cxx11::basic_string<char>]’
prog.cpp:35:45:   required from ‘const bool LexicalCastable<std::__cxx11::basic_string<char>, std::__cxx11::basic_string<char> >::value’
prog.cpp:19:3:   required by substitution of ‘template<class To, class From> typename std::enable_if<(((((! std::is_constructible<To, From>::value) && (! std::is_same<std::__cxx11::basic_string<char>, To>::value)) && (! std::is_same<std::__cxx11::basic_string<char>, From>::value)) && LexicalCastable<From, std::__cxx11::basic_string<char> >::value) && LexicalCastable<std::__cxx11::basic_string<char>, To>::value), To>::type lexicalCast(const From&) [with To = std::__cxx11::basic_string<char>; From = <missing>]’
prog.cpp:40:43:   required from here
prog.cpp:29:49: fatal error: template instantiation depth exceeds maximum of 900 (use -ftemplate-depth= to increase the maximum)
   -> decltype(lexicalCast<TT>(std::declval<From>()), std::true_type{});
                               ~~~~~~~~~~~~~~~~~~^~

最佳答案

how can I solve this problem to be able to compile this code with GCC

您可以使用保证短路的std::conjunction (C++17)

template <typename To, typename From>
typename std::enable_if<
    std::conjunction<
           std::negation<std::is_same<std::string, To>>,
           std::negation<std::is_same<std::string, From>>,
           LexicalCastable<From, std::string>
           LexicalCastable<std::string, To>>::value,
    To>::type
lexicalCast(const From &from)
{
    return lexicalCast<To>(lexicalCast<std::string>(from));
}

关于c++ - 无限模板递归,因为仅使用 gcc 没有 bool 表达式优化,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55144761/

相关文章:

c++ - 将 Foo& 添加到 std::vector

c++ - 在 C++ 中存储和打印 10+ 位整数

C++链表节点引用自身

c++ - 使用 Boost 传递类函数时出现无效模板错误

c - 如何告诉 gcc 在头文件的包含文件夹中查找?

c++ - 如何对 vector 中的字符串进行模式匹配?

c++ - boost::interprocess scoped_allocator 和不在共享内存中的容器的容器

c++ - 模板部分特化防止从派生类初始化

linux - 包含路径错误?

c - 使用C语言进行图形化(GCC编译器)