c++ - Monty Hall 模拟中的意外结果

Question

根据我读到的概率，切换门应该有大约 66% 的机会选择正确的门。下面这段代码是我想出的，它吐出大约 50% 的胜利，而不是我期望的 66%。任何关于我在这里出错的地方的帮助将不胜感激。

for (int count = 0; count < 10000; count++)
{
    // Chooses which door contains DAT GRAND PRIZE YO.
    wDoor = rand() % 3 + 1;

    // AI Contestants Door choice
    aiDoor = rand() % 3 + 1;

    // Using oldChoice to ensure same door isn't picked.
    oldChoice = aiDoor;
    // Used in determining what door to open.
    openedDoor = aiDoor;

    // "Open" a door that is not the winning door and not the door chosen by player.
    do
    {
                openedDoor = rand() % 3 + 1;

    }while (openedDoor != wDoor && openedDoor != aiDoor);

    // Select new door between the remaining two.
    do
    {
              aiDoor = rand() % 3 + 1;

    }while (aiDoor != oldChoice && aiDoor != openedDoor);

    // Increment win counter if new door is correct.
    if (aiDoor == wDoor)
    {
               chooseAgain++;
    }

}

Answer 1

您的 while 条件是错误的:

while (openedDoor != wDoor && openedDoor != aiDoor)

应该是

while (openedDoor == wDoor || openedDoor == aiDoor)

等等