c++ - 不会等待 getline C++

Question

<分区>

Answer 1

这是使用 getline() 函数的简单方法:

#include <iostream>
#include <string>

using namespace std;

int main(void)
{
    string name;
    int age;

    cout << "How old are you ?" << endl;
    cin >> age;

    cin.ignore();              // for avoiding trouble with 'name' when we're gonne use getline()

    cout << "What's your name ?" << endl;
    getline(cin, name); 

    system("PAUSE");
}

别忘了，如果你在 getline() 之前使用 cin，你必须输入以下行:

cin.ignore();

所以你的代码应该看起来像这样:

int main()
{
    vector<person> people;
    bool flag = true;
    int num_people = 0;
    //char*filename="names.txt";

    people = read_file();

    while(flag)
    {
        int sel = 0;
        string args;
        cout << "1 - Sök del av personnamn" << "\n" << "2 - Sök städer" << "\n" << "3 - Avsluta" << endl;
        cin >> sel;

        cin.ignore()

        if(sel == 1)
        {
            cout << "Mata in delen av personnamnet" << endl;
            getline(cin, args);
            print_result(find_in_names(people, args));
        }
        else if(sel == 2)
        {
            cout << "Mata in staden" << endl;
            getline(cin, args);
            args = lower_letters(args);
            print_result(find_person_from_city(people, args));
        }
        else if(sel==3)
        {
            flag=false;
        }
        else
        {
            cout << "FEL, TRYCK OM!" << endl;
        }
    }
}

这是一些文档 http://www.cplusplus.com/reference/istream/istream/ignore/ ，希望对您有所帮助；