我正在尝试学习指针,但出现此错误。需要改头文件类Request吗?为什么我会收到这样的错误?
cannot convert `req' from type `Request' to type `Request *'
错误发生在这些行中:
//Store necessary information in a Request object for each request.
Request req(url, request, 1);
Request *reqq = req; //req points to the object
list->Append(reqq);
代码:
void
ClientThread(int request)
{
const int sz = 50;
char url[sz];
FILE *fp = fopen("url.txt", "r");
if (!fp)
printf(" Cannot open file url.txt!\n");
else {
int pos = 0;
char c = getc(fp);
while (c != EOF || pos == sz - 1) {
if (c == '\n') {
url[pos] = '\0';
serve(url);
pos = 0;
//Store necessary information in a Request object for each request.
Request req(url, request, 1);
Request *reqq = req; //req points to the object
list->Append(reqq);
}
else {
url[pos++] = c;
}
c = getc(fp);
}
fclose(fp);
}
}
我的 request.h 文件包含以下内容:
class Request
{
public:
//constructor intializes request type
Request(char *u, int rqtID, int rqtrID);
char *url;
int requestID;
int requesterID;
最佳答案
您需要使用 address-of operator这里:
Request *reqq = &req; //req points to the object
// -------------^
注意 &
在这种情况下 does not mean reference .
If the operand is an lvalue expression of some type T, operator& creates and returns a prvalue of type T*.
关于c++ - 类型错误和指针混淆,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26048757/