我目前正在开发井字游戏。我需要制作一个 Tic Tac Toe 棋盘,每次玩家或计算机移动时它都会更新(显示“X”和“O”。)。到目前为止,我已经成功制作了该板,但我不知道如何有效地将用户的输入转换为“X”。我做的第一件事是发送类似这样的垃圾邮件:
if(playerChoice == 1)
block[0][0] = "X";
if(playerChoice == 2)
block[0][1] = "X";
if(playerChoice == 3)
block[0][2] = "X";
if(playerChoice == 4)
block[1][0] = "X";
if(playerChoice == 5)
block[1][1] = "X";
if(playerChoice == 6)
block[1][2] = "X";
if(playerChoice == 7)
block[2][0] = "X";
if(playerChoice == 8)
block[2][1] = "X";
if(playerChoice == 9)
block[2][2] = "X";
虽然它有效,但它可能是最糟糕的格式。 (现在它有效地将玩家的选择放入正确的方 block 中。)
这是完整的代码(它还没有完成,甚至可能无法运行。):
#include <iostream>
#include <ctime>
#include <cstdio>
#include <cstdlib>
using namespace std;
int main()
{
//random starting turn chooser
int turnFirst; //variable to decide whoever goes first
int computerRandomPick; //variable to decide which grid the computer will place "O"
srand(time(0));
turnFirst = rand()% (2 - 1 + 1)+1;//generates starting person.
computerRandomPick = rand()% (9 - 1 + 1)+1;//computer first random pick
//board arrays
string block[3][3];
block [0][0] = {" "};
block [0][1] = {" "};
block [0][2] = {" "};
block [1][0] = {" "};
block [1][1] = {" "};
block [1][2] = {" "};
block [2][0] = {" "};
block [2][1] = {" "};
block [2][2] = {" "};
//player interaction
int playerChoice;
//BEGIN OF PROGRAM
cout << "Welcome to Tic Tac Toe!" <<endl<< endl;
if(turnFirst == 1)//player first
{
cout << "Please choose a grid to place (X): "<<endl<<endl;
cout << " 1 | 2 | 3"<< endl;
cout << " -----+-----+-----" << endl;
cout << " 4 | 5 | 6" << endl;
cout << " -----+-----+-----" << endl;
cout << " 7 | 8 | 9" << endl;
cout << " -----+-----+-----" << endl<<endl;
cin >> playerChoice;
system("CLS");
}
if(playerChoice == 1)
block[0][0] = "X";
if(playerChoice == 2)
block[0][1] = "X";
if(playerChoice == 3)
block[0][2] = "X";
if(playerChoice == 4)
block[1][0] = "X";
if(playerChoice == 5)
block[1][1] = "X";
if(playerChoice == 6)
block[1][2] = "X";
if(playerChoice == 7)
block[2][0] = "X";
if(playerChoice == 8)
block[2][1] = "X";
if(playerChoice == 9)
block[2][2] = "X";
if(turnFirst == 2)//computer first
{
system("CLS");
cout << "The computer picked: " <<endl<<endl;
}
if(computerRandomPick == 1)
block[0][0] = "O";
if(computerRandomPick == 2)
block[0][1] = "O";
if(computerRandomPick == 3)
block[0][2] = "O";
if(computerRandomPick == 4)
block[1][0] = "O";
if(computerRandomPick == 5)
block[1][1] = "O";
if(computerRandomPick == 6)
block[1][2] = "O";
if(computerRandomPick == 7)
block[2][0] = "O";
if(computerRandomPick == 8)
block[2][1] = "O";
if(computerRandomPick == 9)
block[2][2] = "O";
//Game Board.
cout << " " << block[0][0] << " | " << block [0][1] << " | " << block [0][2] << endl;
cout << " -----+-----+-----" << endl;
cout << " " << block [1][0] << " | " << block [1][1] << " | " << block [1][2] << endl;
cout << " -----+-----+-----" << endl;
cout << " " << block [2][0] << " | " << block [2][1] << " | " << block [2][2] << endl;
cout << " -----+-----+-----" << endl;
return 0;
}
最佳答案
假定 block [3][3]声明为:
char block[3][3];
playerChoice 可以是 1-9。 因此,您可以优化为:
playerChoice --; // to make it 0-8
block[playerChoice / 3][playerChoice %3] = 'X'; // instead of "X"
关于C++:如何获取用户输入并将其放入井字棋盘,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26172996/