c++ - Htoi 10 位数字的输出不正确

Question

当我输入 0x123456789 我得到不正确的输出，我不知道为什么。起初我以为这是一个最大可能的 int 值问题，但是我将我的变量更改为 unsigned long 并且问题仍然存在。

#include <iostream>
using namespace std;

long htoi(char s[]);

int main()
{
    cout << "Enter Hex \n";
    char hexstring[20];
    cin >> hexstring;
    cout << htoi(hexstring) << "\n";

}

//Converts string to hex
long htoi(char s[])
{
    int charsize = 0;
    while (s[charsize] != '\0')
    {
        charsize++;
    }
    int base = 1;
    unsigned long total = 0;
    unsigned long multiplier = 1;
    for (int i = charsize; i >= 0; i--)
    {
        if (s[i] == '0' || s[i] == 'x' || s[i] == 'X' || s[i] == '\0')
        {
            continue;
        }
        if ( (s[i] >= '0') && (s[i] <= '9') )
        {
            total = total + ((s[i] - '0') * multiplier);
            multiplier = multiplier * 16UL;
            continue;
        }
        if ((s[i] >= 'A') && (s[i] <= 'F'))
        {
            total = total + ((s[i] - '7') * multiplier); //'7' equals 55 in decimal, while 'A' equals 65
            multiplier = multiplier * 16UL;
            continue;
        }
        if ((s[i] >= 'a') && (s[i] <= 'f'))
        {
            total = total + ((s[i] - 'W') * multiplier); //W equals 87 in decimal, while 'a' equals 97
            multiplier = multiplier * 16UL;
            continue;
        }
    }
    return total;
}

Answer 1

long 在您的计算机上可能也是 32 位。试试 long long。