c++ - 计算机从 1 到 1000 猜测您的号码(必须尝试 10 次)

Question

好的，首先，我是计算机科学类(class)的完全初学者。我可以问我的老师，但我没有时间这样做。因此，请期待一些我看不到的非常愚蠢的错误，而我正在使用 eclipse。

这是我的代码:

#include <iostream>
using namespace std;

int something()
{
    int big = 1000;//largest number is 1000
    int small = 1;//smallest number is 1

    //so, best guess is to go in the middle
    int c;//my guesses
    int inequality;//used to write if statements

    for (int a = 0; a <= 10; a++)
    {
        cout << "Think about a number between 1-1000" << endl;//what console tells you
        c = (big - small) / 2;//my guess will be the midpoint of the two numbers
        while (big > small)//while the highest number is ALWAYS greater than the lowest number
        {
            cout << "Is your number less than, equal to, or greater than my guess? 1-less,2-equal,3-greater" << c << endl;
            cin >> inequality;//you tell me whether my guess is too high, low, or equal
            if (inequality == 1)//if you say it is too low...
            {
                small = c;//the smallest number is now my last guess
                c = c - (big - small) / 2;//so, I'll take the midpoint of the CURRENT biggest and smallest number
            }
            else if (inequality == 2)//if you say it is equal...
            {
                cout << "Yay, I guessed your number." << endl;//cool.
            }
            else if (inequality == 3)//if you say it is too high...
            {
                big = c;//biggest number is now my guess
                c = c + (big - small) / 2;//so, I'll take the midpoint of the CURRENT biggest and smallest number
            }
        }
    }
    system("pause");
    return 0;//returns something in int main function
}

int main()
{
    something();//so I can actually do code.
}

所以我的问题:

如果我在控制台输入第一次猜测后输入 1，我得到 499，这很好。第二次猜测后(我输入 1)，我得到 249，这也很好。但是，我输入 1 后第三次猜测随机得到 681，所以有人可以帮助我吗？

如果您没有为我重写整个代码，我将不胜感激，否则当我上交时，这真的很可疑。我很挣扎，因为我没有很好的计算机科学背景，所以要改进，我主要需要想法。最后，任何能让我的代码看起来更专业一点的方法都将不胜感激:)

此外，我不确定我的 for 循环可能有点偏离。

Answer 1

当你计算下一个数字时你需要改变范围

所以你有第一个

small     guess     big
+---------+----------+

如果用户说太小，则答案高于猜测，因此在范围内 big - guess 这就是你需要切成两半的东西，而不是

c = c - (big - small)/2

guess = (big - guess) / 2 + guess

如果用户说太大，那么答案介于猜测和小之间

guess = (guess - small) / 2 + small