考虑这些参数:
char words[8] = "one two";
string word1;
string word2;
stringstream ss;
这段代码的输出:
ss << strtok(words, " ");
ss >> word1;
ss << strtok(NULL, " ");
ss >> word2;
cout << "Words: " << word1 << " " << word2 << endl;
是:
Words: one
这段代码
ss << strtok(words, " ");
ss >> word1;
char* temp = strtok(NULL, " ");
word2 = temp;
cout << "Words: " << word1 << " " << word2 << endl;
输出是:
Words: one two
为什么stringstream
可以处理strtok
的第一个返回值,但不能处理第二个?
最佳答案
你应该插入语句
ss.clear();
清除流的eof状态。例如
char words[8] = "one two";
std::string word1;
std::string word2;
std::stringstream ss;
ss << std::strtok(words, " ");
ss >> word1;
ss.clear();
ss << std::strtok(NULL, " ");
ss >> word2;
std::cout << "Words: " << word1 << " " << word2 << std::endl;
关于c++ - 为什么 strtok 不能与 stringstream 一起使用?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20814378/