<分区>
考虑以下几点:
template<typename R>
struct call {
template<typename F, typename... Args>
explicit call(F&& f, Args&&... args);
R result;
};
template<typename R, typename F, typename... Args>
call<R>::call(F&& f, Args&&... args)
: result(std::forward<F>(f)(std::forward<Args>(args)...)) { }
clang 对我大喊:
utility.tpp:40:1: error: too many template parameters in template redeclaration
template<typename R, typename F, typename... Args>
^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
utility.hpp:36:5: note: previous template declaration is here
template<typename R>
^~~~~~~~~~~~~~~~~~~~
我真的很困惑。有可能吗？