我自己写字符串类。我重载了 + 运算符。它工作正常,但后来我试图等同于 cstr = str +pop
,它什么也没做。 `你可以在 main() 函数中看到我的错误。编译器没有给出任何错误。
#include <iostream>
#include <string.h>
#include <stdlib.h>
using namespace std;
class S {
public:
S();
S(const char *str);
S(const S &s);
~S() { delete []string;}
S &operator =(const S &s);
int lenght() const {return l ;}
char* strS() const {return string;}
friend ostream &operator <<(ostream &, const S &first) {cout<<first.string;}
friend S operator+ (const S& first, const S& second);
private:
char *string;
int l;
};
int main(){
S pop("Q6");
S str("M5");
S cstr = str +pop; // works correct
cout<<str;
str = str + pop;
cout<<str ; // doesnt work, it doesnt write in terminal
return 0;
}
S::S()
{
l = 0;
string = new char[1];
string[0]='\0';
}
S::S(const char *str)
{
l = strlen(str);
string = new char[l+1];
memcpy(string, str, l+1);
}
S::S(const S &s)
{
l = s.l;
string = new char[l+1];
memcpy(string,s.string,l+1);
}
S &S::operator=(const S &s)
{
if (this != &s)
{
delete []string;
string = new char[s.l+1];
memcpy(string,s.string,s.l+1);
return *this;
}
return *this;
}
S operator +(const S& first, const S& second)
{
S temp;
temp.string = strcat(first.strS(),second.strS());
temp.l = first.lenght() + second.lenght();
return temp;
}
我期待着您的帮助。
最佳答案
您的运算符(operator)有错误!
S temp;
//^^^^ has only one byte buffer!!!
temp.string = strcat(first.strS(),second.strS());
// 1 byte ^^^^^ strcat appends second.strS to first.strS
你应该为 temp 重新分配内存:
S temp;
temp.l = first.lenght() + second.lenght();
delete [] temp.string; // !!!! -
temp.string = new char[temp.l + 1]; // !!!!
// you should have another c-tor which can allocate memory!!!
// like: S(unsigned length, unsigned char c = '\0')
strcpy(temp.string, first.strS());
strcat(temp.string, second.strS());
除了这个明显的错误 - 你还应该注意异常 - 例如 std::bad_alloc
。查看 copy-and-swap 习惯用法以获得更好的方法来完成此任务。
关于c++ - 重载运算符 +。字符串类,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12859568/