c++ - 谁能告诉我为什么显示 "runtime error"？

Question

我正在尝试实现哈希表，但在 createHashTable() 函数的 for 循环中遇到运行时错误。谁能告诉我为什么会显示这个“运行时错误”？是 StackOverflow 错误吗？

#include <iostream>
using namespace std;

#define LOAD_FACTOR 20

struct ListNode{
    int data;
    struct ListNode *next;
};

struct HashTableNode{
    int bCount; // number of elements in the block
    struct ListNode *next;
};

struct HashTable{
    int tSize;  // table size
    int count;  // total number of elements in the table
    struct HashTableNode **hashTableNodeArray;
};

int hashFunction(struct HashTable *h, int data){
   return data % h->tSize;
}

struct HashTable * createHashTable(int numberOfElements){
   struct HashTable *h = new HashTable;
   h->count = 0;
   h->tSize = numberOfElements / LOAD_FACTOR;
   h->hashTableNodeArray = new HashTableNode *[h->tSize];
       for(int i = 0; i < h->tSize; ++i){
       // this is where it is showing runtime error
       h->hashTableNodeArray[i]->bCount = 0;
       h->hashTableNodeArray[i]->next = nullptr;
   }
   return h;
}

void deleteHashTable(struct HashTable *h){
   struct ListNode *node, *tmp;
   for(int i = 0; i < h->tSize; ++i){
       node = h->hashTableNodeArray[i]->next;
       while(node != nullptr){
           tmp = node;
           node = node->next;
           delete tmp;
       }
   }
   delete[] h->hashTableNodeArray;
   delete h;
}

int main(int argc, char **argv){
   struct HashTable *h = createHashTable(220);
   deleteHashTable(h);
   return 0;
}

Answer 1

h->hashTableNodeArray = new HashTableNode *[h->tSize];

这分配了一个指针数组，但不是实际的哈希表节点。在下面的循环中，您尝试写入它们，这是未定义的行为。

你在你的循环中丢失了:

h->hashTableNodeArray[i] = new HashTableNode;