我正在尝试从内部类方法 iterateForward
访问外部类变量 cell[i][j]
。
我不想将外部类的 this
作为 iterateForward(Matrix&)
传递给 iterateForward
,因为它会向 iterateForward 添加一个参数.
内部类方法:
Pos Matrix::DynamicCellIterator::iterateForward(){
....................
(Example) outerRef.cell[i][j].isDynamic = true;
.....................
}
这是我的类(class):
class Matrix {
class DynamicCellIterator{
Cell* currentCellPtr;
Matrix& outerRef; //This will be the key by which i'll get access of outer class variables
public:
DynamicCellIterator(Matrix&);
Pos iterateForward();
};
Cell cell[9][9];
DynamicCellIterator dynIte(*this); // I have a problem of initializing the outerRef variable.
Error errmsg;
bool consistent;
public:
Matrix();
Matrix(Matrix&);
................
}
//Here I tried to initialize the outerRef.
Matrix::DynamicCellIterator::DynamicCellIterator(Matrix& ref){
this->currentCellPtr = NULL;
this->outerRef = ref;
}
如何初始化 outerRef
?
最佳答案
您需要在构造函数的初始化列表中初始化成员引用。对 dynIte
成员做同样的事情:在 outer 的构造函数中初始化它。
像这样:
class Outer {
class Inner {
int stuff;
Outer &outer;
public:
Inner(Outer &o): outer(o) {
// Warning: outer is not fully constructed yet
// don't use it in here
std::cout << "Inner: " << this << std::endl;
};
};
int things;
Inner inner;
public:
Outer(): inner(*this) {
std::cout << "Outer: " << this << std::endl;
}
};
关于c++ - C++中如何从内部类访问外部类对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9047302/