应该是一个非常简单的修复...
我有一个注册表单,我想验证它的空字段,并让 JavaScript 在必要时返回一个简单的弹出警报。这是脚本代码:
<script type="text/javascript">
function validateForm() {
var a = document.forms["registration_form"]["school"].value;
var b = document.forms["registration_form"]["name"].value;
var c = document.forms["registration_form"]["password"].value;
var d = document.forms["registration_form"]["field"].value;
var e = document.forms["registration_form"]["field_location"].value;
var f = document.forms["registration_form"]["volleyball_campus"].value;
var g = document.forms["registration_form"]["volleyball_location"].value;
var h = document.forms["registration_form"]["indoor"].value;
var i = document.forms["registration_form"]["outdoor_courts"].value;
var j = document.forms["registration_form"]["blackout"].value;
var k = document.forms["registration_form"]["blackout_dates"].value;
if (a == "" || b == "") {
alert("Please make sure to enter your name and school.");
return false;
} else if (c != "pal") {
alert("Sorry, your password is invalid.");
return false;
} else if (d == "no" && e == "") {
alert("Please make sure to enter where you will play football.");
return false;
} else if (f == "no" && g == "") {
alert("Please make sure to enter where you will play volleyball.");
return false;
} else if (h == "no" && i == "0") {
alert("Please make sure to select how many outdoor volleyball courts you will use.");
return false;
} else if (j == "yes" && k == "") {
alert("Please make sure to enter your blackout dates.");
return false;
}
}
</script>
变量 a、b 和 c 一切正常。然而,以变量 d && e 开头的 else if 条件似乎没有执行。我想我的措辞肯定有问题,但我不知道它是什么。
我已经将服务器端 php 脚本设置为执行完全相同的操作,并且它可以正常工作。您可以在这里看到它:
//Validate the form:
if ($_POST['school'] == "" || $_POST['name'] == "") {
echo "Please make sure to enter your name and school.";
} elseif ($_POST['password'] != "pal") {
echo "Sorry, your password is invalid.";
} elseif ($_POST['field'] == "no" && $_POST['field_location'] == "") {
echo "Please make sure to enter where you will play football.";
} elseif ($_POST['volleyball_campus'] == "no" && $_POST['volleyball_location'] == "") {
echo "Please make sure to enter where you will play volleyball.";
} elseif ($_POST['indoor'] == "no" && $_POST['outdoor_courts'] == "0") {
echo "Please make sure to select how many outdoor volleyball courts you will use.";
} elseif ($_POST['blackout'] == "yes" && $_POST['blackout_dates'] == "") {
echo "Please make sure to enter your blackout dates.";
} else {
这按照我想要的方式捕获了所有内容,但是客户端 Javascript 验证(我首先运行它只是为了获得更用户友好的外观)似乎无法超越前三个变量。
我一生都无法弄清楚为什么。我在互联网上进行了搜索,但找不到我正在寻找的答案。任何帮助将不胜感激!
附注该页面本身位于http://www.712jefferson.org/pal/registration.html ,如果这有助于阐明预期的过程。
最佳答案
仅当 d
等于 no
并且 e
留空时才会显示警报。这同样适用于 f
和 g
。这没有道理。举个例子:
我打 Volley
,但不在校园打球,所以我在f
中输入no
,你的逻辑希望我输入一个空字符串在 g
中,您确实希望用户输入 Volley 位置。
这应该更改为:
else if (f == "no" && g != "") {
}
请注意从 ==
到 !=
的更改,这意味着 g
不等于空字符串。这同样适用于 d
和 e
(如果 d
设置为,您不希望 e
为空“不”)。
此外,在客户端验证您的密码是有风险的,我希望您进行服务器端验证。
关于php - Javascript - If 条件由 "&&"分隔(需要建议),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18280095/