javascript - 如何将缺失的项目添加到 JavaScript 数组中？

Question

我有以下 JavaScript 数组:

[
    {
        "day": 0,
        "best_hour_of_the_day": "10",
        "appt_success_rate": "60",
        "appt_100_numbers": "27"
    },
    {
        "day": 2,
        "best_hour_of_the_day": "10",
        "appt_success_rate": "60",
        "appt_100_numbers": "27"
    },
    {
        "day": 3,
        "best_hour_of_the_day": "10",
        "appt_success_rate": "60",
        "appt_100_numbers": "27"
    },
    {
        "day": 4,
        "best_hour_of_the_day": "10",
        "appt_success_rate": "60",
        "appt_100_numbers": "27"
    },
    {
        "day": 6,
        "best_hour_of_the_day": "--",
        "appt_success_rate": "0",
        "appt_100_numbers": "0"
    }
]

我已经定义了数组，其中包含我需要的天数。

var daysOfTheWeek = [0,1,2,3,4,5,6];

我想问一下，如何将缺失项添加到 JavaScript 数组中的好方法是什么？

这意味着添加缺失值 1 和 6 以获得以下 JavaScript 结果:

[
    {
        "day": 0,
        "best_hour_of_the_day": "10",
        "appt_success_rate": "60",
        "appt_100_numbers": "27"
    },
    {
        "day": 1,
        "best_hour_of_the_day": "--",
        "appt_success_rate": "0",
        "appt_100_numbers": "0"
    },
    {
        "day": 2,
        "best_hour_of_the_day": "10",
        "appt_success_rate": "60",
        "appt_100_numbers": "27"
    },
    {
        "day": 3,
        "best_hour_of_the_day": "10",
        "appt_success_rate": "60",
        "appt_100_numbers": "27"
    },
    {
        "day": 4,
        "best_hour_of_the_day": "10",
        "appt_success_rate": "60",
        "appt_100_numbers": "27"
    },
    {
        "day": 5,
        "best_hour_of_the_day": "10",
        "appt_success_rate": "60",
        "appt_100_numbers": "27"
    },
    {
        "day": 6,
        "best_hour_of_the_day": "--",
        "appt_success_rate": "0",
        "appt_100_numbers": "0"
    }
]

Answer 1

我在 JAVASCRIPT 中给出了解决方案:

查看演示:

jsfiddle 链接: http://jsfiddle.net/3phba87q/

给出:

var dummyData=[
        {
            day: 0,
            best_hour_of_the_day: "10",
            appt_success_rate: "60",
            appt_100_numbers: "27"
        },
        {
            day: 2,
            best_hour_of_the_day: "10",
            appt_success_rate: "60",
            appt_100_numbers: "27"
        },
        {
            day: 3,
            best_hour_of_the_day: "10",
            appt_success_rate: "60",
            appt_100_numbers: "27"
        },
        {
            day: 4,
            best_hour_of_the_day: "10",
            appt_success_rate: "60",
            appt_100_numbers: "27"
        },
        {
            day: 5,
            best_hour_of_the_day: "10",
            appt_success_rate: "60",
            appt_100_numbers: "27"
        }
    ];
var daysOfTheWeek = [0,1,2,3,4,5,6];

为了得到预期的结果:

var existingDays = [];
// get the existing days

for(var i=0;i<dummyData.length;i++){
    existingDays[i] = dummyData[i]['day'];
}

// check which day's data is missing; then create a dummy object and push it to the dummyData object

for(var i=0;i<daysOfTheWeek.length;i++){
   if(existingDays.indexOf(parseInt(daysOfTheWeek[i])) < 0){
       var dummyObject = {
        "day": i,
        "best_hour_of_the_day": "--",
        "appt_success_rate": "0",
        "appt_100_numbers": "0"
       };
       dummyData.push(dummyObject);
   }
}

//sort day wise ascending

dummyData.sort(function(x,y){ return parseInt(x.day) - parseInt(y.day) });