javascript - 干净的箭头函数 - 对数组中的多个元素调用生成器

Question

我正在尝试使用一个干净的箭头函数来调用yield fork(....)。我身边很多地方都出现过这种情况。我正在尝试这样做:

const { ids } = yield take('REQUEST');

// ids is array of numbers [1, 2, 3]

ids.forEach(id => yield fork(requestWorker, id)); ////// this is what im trying to do - this is pseudo-code i know you cant use in non-generators (non-super-star functions)

但是这不起作用，我必须这样做:

for (const id of ids) {
    yield fork(requestWorker, id);
}

而不是:

ids.forEach(id => yield fork(requestWorker, id)); // this is pseudo-code i know you cant use in non-generators (non-super-star functions)

有没有比 for-of 循​​环更简洁的方法？喜欢这个箭头函数方法吗？

Answer 1

你可以产生另一个生成器

function* take(x) {
    var id = /* ... */,
        requesWroker = /* ... */;

    yield* fork(requesWroker, id);
}

var all = [...take('REQUEST')];