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我正在研究以下取自 MDN 的示例:
function doSomething(){}
doSomething.prototype.foo = "bar";
var doSomeInstancing = new doSomething();
doSomeInstancing.prop = "some value";
console.log("doSomeInstancing.prop: " + doSomeInstancing.prop);
console.log("doSomeInstancing.foo: " + doSomeInstancing.foo);
console.log("doSomething.prop: " + doSomething.prop);
console.log("doSomething.foo: " + doSomething.foo);
console.log("doSomething.prototype.prop: " + doSomething.prototype.prop);
console.log("doSomething.prototype.foo: " + doSomething.prototype.foo);
产生以下输出:
doSomeInstancing.prop: some value
doSomeInstancing.foo: bar
doSomething.prop: undefined
doSomething.foo: undefined
doSomething.prototype.prop: undefined
doSomething.prototype.foo: bar
我不明白为什么 doSomething.foo 是未定义的。 foo 被添加到 doSomething 的原型(prototype)中,一旦在对象的实例中找不到它,解释器不应该在那里找到它吗?