javascript - 匹配正则表达式 : [everything before number], [数字]

Question

我在一堆变化很大的字符串上使用.match()。我想从字符串中获取括号内的最后一个数字，然后从那里获取之前的所有内容。例如:

1 serving  (57.0 g)
1 slice, small (2" x 2-1/2" x 1-3/4")  (32.0 g)

成为数组:

['1 serving', '57.0 g']
['1 slice, small (2" x 2-1/2" x 1-3/4")', '32.0 g']

各种字符串的列表:http://regex101.com/r/jJ5sF3/1

我一直在努力编写一个正则表达式来捕获这一点。

Answer 1

使用此模式

(.*\S)\s*\(([^()]+)  

Demo

(               # Capturing Group (1)
  .             # Any character except line break
  *             # (zero or more)(greedy)
  \S            # <not a whitespace character>
)               # End of Capturing Group (1)
\s              # <whitespace character>
*               # (zero or more)(greedy)
\(              # "("
(               # Capturing Group (2)
  [^()]         # Character not in [^()]
  +             # (one or more)(greedy)
)               # End of Capturing Group (2)