javascript - 正则表达式:匹配，但不包括匹配的部分

Question

这是正文:

https://www.google.com/url?rct=3Dj\u0026sa=3Dt\u0026url=3Dhttps://rivesjournal.com/inside-track-trading-focus-on-shares-of-adobe-systems-inc-adbe/48453/\u0026ct=3Dga\u0026cd=3DCAEYASoTOT

我想获取实际链接:

https://rivesjournal.com/inside-track-trading-focus-on-shares-of-adobe-systems-inc-adbe/48453/

/=3Dhttps.*\//g 包含 =3D，但我想去掉它。我该如何解决这个问题？

这是 regex .

Answer 1

一个选项是通过使用带有 ^ anchor 的否定前瞻来防止第一个 http.* 子串被匹配:

Example Here

(?!^)https:.*\/

这基本上匹配 https:.*\/ 只要它不在字符串的开头。

片段:

var string = 'https://www.google.com/url?rct=3Dj\u0026sa=3Dt\u0026url=3Dhttps://rivesjournal.com/inside-track-trading-focus-on-shares-of-adobe-systems-inc-adbe/48453/\u0026ct=3Dga\u0026cd=3DCAEYASoTOT';

console.log(string.match(/(?!^)https:.*\//)[0]);

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但是，上面的表达式不会涵盖所有边缘情况，因此更好的选择是只使用捕获组:

Updated Example

=3D(https.*\/)

片段:

var string = 'https://www.google.com/url?rct=3Dj\u0026sa=3Dt\u0026url=3Dhttps://rivesjournal.com/inside-track-trading-focus-on-shares-of-adobe-systems-inc-adbe/48453/\u0026ct=3Dga\u0026cd=3DCAEYASoTOT';

console.log(string.match(/=3D(https.*\/)/)[1]);

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您还可以使用否定字符类，例如 [^\\]+ 以匹配一个或多个非 \ 字符:

Updated Example

=3D(https[^\\]+)