我不确定为什么我的代码会出现错误。我做错了什么？
<!DOCTYPE html>
<html lang="en">
<head>
<!-- Required meta tags -->
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no">
<!-- Bootstrap CSS -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0-alpha.6/css/bootstrap.min.css" integrity="sha384-rwoIResjU2yc3z8GV/NPeZWAv56rSmLldC3R/AZzGRnGxQQKnKkoFVhFQhNUwEyJ" crossorigin="anonymous">
<script src="https://code.jquery.com/jquery-3.2.1.min.js"></script>
<script>
$( document ).ready(function() {
var logResp = $('#food-hygiene');
logResp.ajax({
url: "food-hygiene.html",
async: false,
type: "GET",
dataType: "string"
}).done( function(data) {
alert(data);
})
});
</script>
</head>
<body>
<div class="container-fluid">
<div class="content-wrapper">
<div id="food-hygiene">Loading...</div>
</div>
</div>
<!-- jQuery first, then Tether, then Bootstrap JS. -->
<script src="https://code.jquery.com/jquery-3.1.1.slim.min.js" integrity="sha384-A7FZj7v+d/sdmMqp/nOQwliLvUsJfDHW+k9Omg/a/EheAdgtzNs3hpfag6Ed950n" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/tether/1.4.0/js/tether.min.js" integrity="sha384-DztdAPBWPRXSA/3eYEEUWrWCy7G5KFbe8fFjk5JAIxUYHKkDx6Qin1DkWx51bBrb" crossorigin="anonymous"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0-alpha.6/js/bootstrap.min.js" integrity="sha384-vBWWzlZJ8ea9aCX4pEW3rVHjgjt7zpkNpZk+02D9phzyeVkE+jo0ieGizqPLForn" crossorigin="anonymous"></script>
</body>
</html>
更新:正如 Satpal 所指出的，有两个对 jQuery 的引用。下一个是不支持 jQuery 的 slim 版本。
最佳答案
logResp 它包含您使用此语句选择的 #food-hygiene 元素的实例:$('#food-hygiene');.
替换这段代码:
logResp.ajax({
url: "food-hygiene.html",
async: false,
type: "GET",
dataType: "string"
}).done( function(data) {
alert(data);
})
有了这个:
jQuery
.ajax(
{
url: "food-hygiene.html",
async: false,
type: "GET",
dataType: "string"
}
)
.done(
function(data) {
alert(data);
}
);
关于javascript - jQuery.ajax 不是函数类型错误，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50528251/