我正在设计一个库存系统,它有用户、产品、buy_leads、订单(授权购买线索)、输入和输出。
class Product < ActiveRecord::Base
has_many :buy_leads
end
class BuyLead < ActiveRecord::Base
belongs_to :product
has_one :order
end
class Order < ActiveRecord::Base
belongs_to :buy_lead
belongs_to :user, :foreign_key => :authorized_by
has_many :inputs
end
class Input < ActiveRecord::Base
belongs_to :order
has_many :outputs
end
class Output < ActiveRecord::Base
# Associations
belongs_to :input
belongs_to :user
end
输入和输出有一个数量值。为了获得产品库存和特定产品库存,我在两个原始 SQL 查询中使用 UNION,通过使输出数量为负数,然后分组和将它们加在一起:
class InventoryController < ApplicationController
def index
@inventory = Input.find_by_sql products_inventory_sql
end
def show
@inventory = Input.find_by_sql product_inventory_sql(params[:id])
end
private
def inputs_sql
"SELECT b.*, p.*, i.order_id,
i.id AS input_id,
i.quantity AS quantity
FROM inputs i
JOIN orders r ON r.id = i.order_id
JOIN buy_leads b ON b.id = r.buy_lead_id
JOIN products p ON p.id = b.product_id"
end
def outputs_sql
"SELECT b.*, p.*, i.order_id,
i.id AS input_id,
(o.quantity * -1) AS quantity
FROM outputs o
JOIN inputs i ON i.id = o.input_id
JOIN orders r ON r.id = i.order_id
JOIN buy_leads b ON b.id = r.buy_lead_id
JOIN products p ON p.id = b.product_id"
end
def products_inventory_sql
"SELECT *, SUM(quantity) AS remaining_qty
FROM (#{inputs_sql} UNION #{outputs_sql})
GROUP BY product_id"
end
def product_inventory_sql(id)
"SELECT *, SUM(quantity) AS remaining_qty
FROM (#{inputs_sql} UNION #{outputs_sql})
WHERE product_id = #{id}
GROUP BY order_id, input_id"
end
end
它有效,但我想使用 named_scope 的特性在 ActiveRecord 中链接查询并能够执行以下操作:
Product.inputs.by_product(id)
Product.inventory.by_product(id)
...
任何想法,或者我是否必须更改模式以获得更方便的模式?谢谢!
最佳答案
解决这个问题的可能性太多了,你到底想从这些报告中得到什么?
买单?产品?输入/输出?
(我将此作为答案发布,因为我无法对您的问题发表评论,如果您能启发我,我会更新答案)
更新
试试这个
#on input
named_scope :by_product, lambda {|id| {:joins => {:orders => {:buy_leads => :products}}, :conditions => ['products.id = ?', id]}}
您可以通过调用获取与该产品 ID 匹配的输入
Input.by_product(25)
如果那是您正在寻找的,我认为您现在也可以设法按产品进行输出:]
关于sql - 没有 UNION 的库存 SQL 查询?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3137224/