JavaScript : How to process function's argument even if it undefined

Question

我正在创建一个函数来检查给定值是否为空，如果未定义、等于空字符串或长度为零，则它将返回 true。这就是我所做的

isEmpty(value){
    if(typeof(value)=='undefined'){
        return true;
    }
    else if(value==''||value.length==0){
        return true;
    }
    return false;
}

但是当我评估一些 undefined variable 时，例如 isEmpty(foo) ，它会抛出一个 Uncaught ReferenceError ，但我想返回 true，该怎么做？

function isEmpty(value) {
  if (typeof(value) == 'undefined') {
    return true;
  } else if (value == '' || value.length == 0) {
    return true;
  }
  return false;
}

console.log(isEmpty(value))

Answer 1

您正在了解Undefined错误

Undefined means a variable has been declared, but the value of that variable has not yet been defined(Not assigned a value yet). For example:

function isEmpty(value){

// or simply value===undefined will also do in your case
  if(typeof(value)==='undefined'||value==''||value.length==0){
        return true;
    }
  return false;
        
}
let foo; // declared but not assigned a value so its undefined at the moment
console.log(isEmpty(foo))


   

添加 - 什么是未捕获引用错误:“x”未定义。

There is a non-existent variable referenced somewhere. This variable needs to be declared , or you need make sure it is available in your current script or scope.

很明显，您没有在上下文中的任何地方引用您的变量，因此您会得到该异常。 Follow Up Link

这是您可以通过捕获引用错误来检查变量是否在范围内或者是否已声明的方法

// Check if variable is declared or not

//let value;
try {
  value;
} catch (e) {
  if (e.name == "ReferenceError") {
    console.log("variable not declared yet")
  }


}

// or the function approach


function isEmpty(value){

// or simply value===undefined will also do in your case
  if(typeof(value)==='undefined'||value==''||value.length==0){
        return true;
    }
  return false;
        
}


try {
  isEmpty(value);
} catch (e) {
  if (e.name == "ReferenceError") {
    console.log("variable not declared yet")
  }
}