在使用 ajax 从 db 绑定(bind)数据时，我无法将复选框添加到我的 DataTable。如何添加带有服务器端数据加载的复选框？
我的 jQuery:
var table = $('#example').DataTable({
"ajax": "getBusperOrder.php",
"bPaginate": true,
"retrieve": true,
"bProcessing": true,
"pageLength": 10,
"columns": [{
mData: 'district'
}, {
mData: 'deponame'
}, {
mData: 'busname'
}, {
mData: 'bonnetnumber'
}, {
mData: 'routename'
}, {
mData: 'bustype'
}, {
mData: 'status'
}
],
});
HTML:
<table id="example">
<thead>
<tr>
<th>District</th>
<th>Depo Name</th>
<th>Bus Number</th>
<th>Bonnet Number</th>
<th>Route Name</th>
<th>Bus Type</th>
<th>Action</th>
</tr>
</thead>
</table>
gerBusperOrder.php
<?php
require('database/db.php');
$sql = "select * from bus as B left join depo as D on B.depoid=D.depoid left join district as DS on D.district=DS.id left join bustype as BS on B.bustypeid=BS.bustypeid left join route as R on B.routeid=R.routeid LEFT JOIN bustype as BT on B.bustypeid=BT.bustypeid WHERE B.busid IN(SELECT busid from bus where busid NOT IN (SELECT DISTINCT(bus_id) from advt_book_side AS ABS INNER JOIN booking as B on ABS.booking_number=B.bookingnumber WHERE B.todate>CURDATE() GROUP BY bus_id HAVING COUNT(sides_id)=4))";
$resultset = mysqli_query($db, $sql) or die("database error:" . mysqli_error($db));
$data = array();
while ($rows = mysqli_fetch_assoc($resultset)) {
$data[] = $rows;
}
$results = array(
"sEcho" => 1,
"iTotalRecords" => count($data),
"iTotalDisplayRecords" => count($data),
"aaData" => $data
);
echo json_encode($results);
?>
我需要在每个带有 id 的 td 的第一列添加一个复选框
最佳答案
您可以雇用 columns.render为此目的的选项:
"columns": [{
mData: 'district'
render: (_,__,rowData) => `<input type="checkbox" value="${rowData.busid}">${rowData.busid}</input>`
},
...
]
关于javascript - 使用ajax从数据库加载数据时将复选框添加到数据表，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/57570064/