我的 JavaScript 函数有问题。它没有按预期工作。看看这个 fiddle -> http://jsfiddle.net/NM3k6/1/ .
这里我有问题,每个问题有三个选择。如果您按照正常流程选择并回答。它会给你们两个正确的答案。现在这是我的问题,回答第一个问题后,再次导航回第一个问题并选择答案。它会立即显示结果,而无需进入下一个问题。
下面是代码。
<center>
<div id="your-curve-id">
<fieldset class="questions" style="border: 1px solid #000; width:500px; margin: 20px">
<h2 id="p1">1. Please select your Curve Id 1</h2>
<ul id="ul1">
<li class="option" name="Curve Id 1" value='Select 1A'>Answer 1</li>
<li class="option" name="Curve Id 1" value='Select 1B'>Answer 2</li>
<li class="option" name="Curve Id 1" value='Select 1C'>Answer 3</li>
</ul>
</fieldset>
<fieldset class="questions" style="border: 1px solid #000; width:500px; margin: 20px">
<h2 id="p2">2. Please select your Curve Id 2</h2>
<ul id="ul2">
<li class="option" name="Curve Id 2" value='Select 2A'>Answer 1</li>
<li class="option" name="Curve Id 2" value='Select 2B'>Answer 2</li>
<li class="option" name="Curve Id 2" value='Select 2C'>Answer 3</li>
</ul>
</fieldset>
</div>
</center>
<div id="results"></div>
这是脚本..
$(document).ready(function(){
answers = new Object();
var totalQuestions = $('.questions').size();
$('.option').click(function(){
console.log($(this).attr('value'));
var answer = ($(this).attr('value'));
var question = ($(this).attr('name'));
answers[question] = answer;
$('#count').html(Object.keys(answers).length + " / " + totalQuestions);
next();
back();
});
var currentQuestion = 0;
$questions = $('.questions');
$('ul#ul2').hide();
function next(){
$($questions.get(currentQuestion)).ready(function(){
currentQuestion = currentQuestion + 1;
if(currentQuestion == totalQuestions){
//do stuff with the result
var result = values();
$('div#your-curve-id').hide();
$('#results').html(result);
}else{
$($questions.get(currentQuestion)).show();
$('ul#ul1').hide();
$('ul#ul2').show('slow');
}
});
}
function values(){
var res = "";
var imahe = "";
for (questions in answers)
{
if (answers.hasOwnProperty(questions)) {
res += questions + '::' + answers[questions] + '<br />' + '<br />';
}
}
return res;
}
function back(){
$('h2#p1').click(function() {
$('ul#ul1').show('slow');
$('ul#ul2').hide();
});
}
});
看看这个 fiddle -> http://jsfiddle.net/NM3k6/1/ .
最佳答案
简短回答:您可以在 next()
中递增 currentQuestion
,但绝不会在 back()
中递减它。
function back() {
$('h2#p1').click(function() {
currentQuestion--;
$('ul#ul1').show('slow');
$('ul#ul2').hide();
});
}
不过,为了获得更好的答案,我建议您将应用了该修复的相同问题提交至 Code Review .
关于Javascript 函数在第二次尝试时不会进入下一个列表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23128434/