java - 如何按即将到来的生日顺序获取联系人？

Question

我有读取联系方式和生日的代码。但是，我如何获得按即将到来的生日排序的联系人列表？

对于由 id 标识的单个联系人，我会像这样获取详细信息和生日:

Cursor c = null;
  try {
   Uri uri = ContentUris.withAppendedId(
     ContactsContract.Contacts.CONTENT_URI, id);
   c = ctx.getContentResolver().query(uri, null, null, null, null);
   if (c != null) {
    if (c.moveToFirst()) {
     DatabaseUtils.cursorRowToContentValues(c, data);
    }

   }
   c.close();

   // read birthday
   c = ctx.getContentResolver()
     .query(
       Data.CONTENT_URI,
       new String[] { Event.DATA },
       Data.CONTACT_ID + "=" + id + " AND "
         + Data.MIMETYPE + "= '"
         + Event.CONTENT_ITEM_TYPE + "' AND "
         + Event.TYPE + "=" + Event.TYPE_BIRTHDAY,
       null, Data.DISPLAY_NAME);
   if (c != null) {
    try {
     if (c.moveToFirst()) {
      this.setBirthday(c.getString(0));
     }
    } finally {
     c.close();
    }
   }

   return super.load(id);
  } catch (Exception e) {
   Log.v(TAG(), e.getMessage(), e);
   e.printStackTrace();
   return false;
  } finally {
   if (c != null)
    c.close();
  }

读取所有联系人的代码是:

public Cursor getList() {
        // Get the base URI for the People table in the Contacts content
        // provider.
        Uri contacts = ContactsContract.Contacts.CONTENT_URI;
        // Make the query.
        ContentResolver cr = ctx.getContentResolver();
        // Form an array specifying which columns to return.
        String[] projection = new String[] { ContactsContract.Contacts._ID,
                ContactsContract.Contacts.DISPLAY_NAME };

        Cursor managedCursor = cr.query(contacts, projection, null, null,
                ContactsContract.Contacts.DISPLAY_NAME
                        + " COLLATE LOCALIZED ASC");
        return managedCursor;
    }

Answer 1

我以相反的方式进行了此操作 - 直接选择存储生日的数据表。

private static final int UPCOMING_COUNT = 10;


public static List<BContact> upcomingBirthday(Context ctx) {
    String today = new SimpleDateFormat("MM-dd").format(new Date());        
    List<BContact> firstPart = upcomingBirthday(ctx, today, "12-31", UPCOMING_COUNT);
    if (firstPart.size() < UPCOMING_COUNT) {
        firstPart.addAll(upcomingBirthday(ctx, "01-01", today, UPCOMING_COUNT - firstPart.size()));
    }
    return firstPart;
}


public static List<BContact> upcomingBirthday(Context ctx, String fromDate, String toDate, int rows) {

  Uri dataUri = ContactsContract.Data.CONTENT_URI;

  String[] projection = new String[] { ContactsContract.Contacts.DISPLAY_NAME,                         
            ContactsContract.CommonDataKinds.Event.CONTACT_ID,
            ContactsContract.CommonDataKinds.Event.START_DATE
            };


  Cursor c = ctx.getContentResolver().query(
       dataUri,
       projection, 
       ContactsContract.Data.MIMETYPE + "= ? AND " + 
       ContactsContract.CommonDataKinds.Event.TYPE + "=" + ContactsContract.CommonDataKinds.Event.TYPE_BIRTHDAY + 
       " AND substr(" + ContactsContract.CommonDataKinds.Event.START_DATE + ",6) >= ?" + 
       " AND substr(" + ContactsContract.CommonDataKinds.Event.START_DATE + ",6) <= ?" ,
       new String[] {ContactsContract.CommonDataKinds.Event.CONTENT_ITEM_TYPE, fromDate, toDate}, 
       "substr("+ ContactsContract.CommonDataKinds.Event.START_DATE +",6)");
  List<BContact> result = new ArrayList<BContact>();
  int i=0;
  while (c.moveToNext() && i<rows) {
      result.add(new BContact(c.getString(0), c.getString(1), c.getString(2)));
      i++;
  }
  c.close();
  return result;

SELECT 被调用两次 - 一次调用从今天到 12/31，第二次调用从 01/01 到今天。我将返回的行限制为 10，但这不是必需的。

编辑:我发现这不适用于所有 Android 手机，因为生日日期以许多不同的格式存储。所以你必须加载所有生日(无序)，解析它并在内存中排序。 #失败