javascript - 在字符串数组中查找特定字符串

Question

在字符串数组中，如果循环发现其中一个字符串不是我们要查找的内容，则返回 false。

如果没有找到不匹配的字符串，则数组是正确的，并且应该返回true。即使数组没有“错误”，它也会不断返回 false

我尝试过使用indexOf、for循环和while循环，但都没有成功。

function brackets() {
    var testArr = ['()', '{}', '()']

    /* Method 1 --- returns false even when the parenthesis are ok, I guess
    it's because the indexOf only searches for the first element that matches 
    the criteria */

    if (testArr.indexOf("()") == -1 || testArr.indexOf("{}") == -1 ||
        testArr.indexOf("[]") == -1) {
        return false
    } else {
        return true
    }

    /* Method 2 --- for loop. Same story, returns false, even when all   
    testArr[i] === any of the cases and none of them is !==, it behaves as if it was 
    false. I'm not sure why */

    for (i = 0; i < testArr.length; i++) {
        if (testArr[i] !== "()" || testArr[i] !== "{}" || testArr[i] !== "[]") {
            return false
        }
    }
    return true
}

brackets()

Answer 1

在第二种方法中，您可以使用 AND 运算符来解决此问题。

function brackets() {
var testArr = ['()', '{}', '()'];

/* Method 2 --- for loop. Same story, returns false, even when all   
testArr[i] === any of the cases and none of them is !==, it behaves as if it was 
false. I'm not sure why */

for (i = 0; i < testArr.length; i++) {
    if (testArr[i] !== "()" && testArr[i] !== "{}"  && testArr[i] !== "[]") {
        return false;
    }
}
return true;
}

brackets();