因此,我的对象中有不确定数量的数组,我需要合并其中的对象。保证数组的长度相同,并且保证对象具有相同的键。
我尝试过迭代它,但由于某种原因,它对数组中每个键中的对象进行了求和。
示例:
var demo = {
"key1": [{"a": 4, "b": 3, "c": 2, "d": 1}, {"a": 2, "b": 3, "c": 4, "d": 5}, {"a": 1, "b": 4, "c": 2, "d": 9}]
"key2": [{"a": 3, "b": 5, "c": 3, "d": 4}, {"a": 2, "b": 9, "c": 1, "d": 3}, {"a": 2, "b": 2, "c": 2, "d": 3}]
};
mergeArrays(demo);
/* Returns:
{
"arbitraryname": [{"a": 7, "b": 8, "c": 5, "d": 5}, {"a": 4, "b": 12, "c": 5, "d": 8}, {"a": 3, "b": 6, "c": 4, "d": 12}]
}
*/
我当前的实现尝试做这样的事情:
var skeleton = {
"a": 0,
"b": 0,
"c": 0,
"d": 0
};
function mergeArrays = function (obj) {
var flat = {};
var keys = _.keys(prod);
var len = obj[keys[0]].length;
flat["arbitraryname"] = [];
for (var i = 0; i < len; i++) {
flat["arbitraryname"].push(skeleton);
}
flat["arbitraryname"].forEach(function (v, k) {
_.forIn(v, function (key, value) {
flat["arbitraryname"][k][key] += value;
});
});
return flat;
}
有没有更简单的方法?它现在似乎还返回一个完全相同的数组。例如:
[{"a": 14, "b": 26, "c": 14, "d": 25}, {"a": 14, "b": 26, "c": 14, "d": 25}, {"a": 14, "b": 26, "c": 14, "d": 25}]
其中每个对象是数组中所有元素的总和。我究竟做错了什么?有没有更简单的方法?
最佳答案
以下内容与问题顶部的注释数组匹配。预期结果有点不清楚
使用Object.keys()
使其变得相当简单。
var demo = {
"key1": [{"a": 4, "b": 3, "c": 2, "d": 1}, {"a": 2, "b": 3, "c": 4, "d": 5}, {"a": 1, "b": 4, "c": 2, "d": 9}],
"key2": [{"a": 3, "b": 5, "c": 3, "d": 4}, {"a": 2, "b": 9, "c": 1, "d": 3}, {"a": 2, "b": 2, "c": 2, "d": 3}]
};
// iterate and map using first array
var res = demo.key1.map(function(item, idx) {
// loop over keys of each object in array and return
// new objects with sums of matching index and keys
return Object.keys(item).reduce(function(obj,key) {
obj[key] = item[key] + demo.key2[idx][key];
return obj;
},{});
});
// print "res" for demo
document.getElementById('pre').innerHTML =JSON.stringify(res, null, 4)
<pre id="pre"></pre>
关于javascript - 如何在 JavaScript 中合并两个对象数组,并对重复对象键的值求和?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34823703/