我创建了一个 html 页面,用户在等待另一个应用程序重新启动时可以查看该页面。我创建了一个 javascript 脚本,它向应用程序发出多个请求,直到应用程序返回 200。但是,当我尝试打开 html 页面时,浏览器会崩溃。任何人都可以看到我的代码有什么问题吗:
var responseStatus = 404;
var numberOfTries = 0;
var request = new XMLHttpRequest();
while(responseStatus != 200){
console.log("Checking if restart has completed. Attempt number: " + numberOfTries);
request.open('GET', 'applicationurl', true);
request.onreadystatechange = function(){
if (request.readyState === 4){
console.log("Request Status: " + request.status);
responseStatus = request.status;
console.log("Response Status: " + request.status);
if (request.status != 200) {
numberOfTries++;
console.log("Restart has not yet completed! NumberOfTries: " + numberOfTries);
}
}
};
request.send();
}
console.log("Server has successfully restarted");
最佳答案
(在我看来)做到这一点的最佳方法是实际结合 @serge1peshcoff 的两个选项。将调用编写为响应失败时调用自身的函数,并在执行此操作时设置超时。对于大多数目的,您不想在前一个请求之后立即发送另一个请求,您需要等待至少一到五秒以防止向服务器发送垃圾邮件(您也没有给出您期望有多少客户端的指示。什么是对你的浏览器不利对服务器来说可能是可怕的,服务器甚至可能在你的网络应用程序完全启动并返回 200 之前就处理请求)。
此外,setTimeout 是比 setInterval 更好的方法,因为您可以在每次往返时显式重置它。
借用@serge:
function tryRequest(numTries) {
var responseStatus = 404;
var request = new XMLHttpRequest();
numTries = numTries || 0;
console.log("Checking if restart has completed. Attempt number: " + numAttempts);
request.open('GET', 'applicationurl', true);
request.onreadystatechange = function(){
numTries++
if (request.readyState === 4){
console.log("Request Status: " + request.status);
responseStatus = request.status;
console.log("Response Status: " + request.status);
if (request.status != 200) {
console.log("Restart has not yet completed! NumberOfTries: " + this.attempts);
setTimeout(tryRequest.bind(null, numTries), 5000); // five seconds
}
}
};
request.send();
console.log("Server has successfully restarted");
}
tryRequest();
关于javascript - 使用Javascript向服务器发送多个请求,直到服务器返回200,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39790706/