我希望它越走越慢,所以我有这个代码:
$(document).ready(function() {
$("button").click(function() {
var moveTime = Math.floor(Math.random() * 1000) + 2000
var slowDown = 1000;
while (moveTime > 0) {
$("div").animate({
left: slowDown + "px"
});
if (slowDown > 0) {
slowDown--;
moveTime = 0;
}
slowDown--;
moveTime--;
}
});
});
div {
position: absolute;
float: left;
margin: 0 0 0 -8400px;
width: 10000px;
height: 100px;
background: repeating-linear-gradient(90deg, #DF0000, #DF0000 100px, #000000 100px, #000000 200px)
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button>Start Animation</button>
<div></div>
但问题是它只播放动画1次。我也尝试过无限循环,但这也不起作用,与按两次按钮第二次没有任何反应相同。
最佳答案
您的代码的问题是,在连续单击时,div
元素已经位于您尝试为其设置动画的left
位置,因此似乎没有发生任何事情.
要解决此问题,请在再次运行动画之前将 left
位置重置回 0
。试试这个:
$(document).ready(function() {
$("button").click(function() {
var moveTime = Math.floor(Math.random() * 1000) + 2000
var slowDown = 1000;
var $div = $('div').css('left', 0); // < reset the position here
while (moveTime > 0) {
$div.animate({
left: slowDown + "px"
});
if (slowDown > 0) {
slowDown--;
moveTime = 0;
}
slowDown--;
moveTime--;
}
});
});
div {
position: absolute;
float: left;
margin: 0 0 0 -8400px;
width: 10000px;
height: 100px;
background: repeating-linear-gradient(90deg, #DF0000, #DF0000 100px, #000000 100px, #000000 200px)
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button>Start Animation</button>
<div></div>
关于javascript动画不循环,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40911371/