我有一个像这样的对象数组
array[0] = {id: 1, name: "First"}
array[1] = {id: 2, name: "Second"}
我尝试使用以下方法按 name
字段排序:
Array.prototype.alphanumSort = function (caseInsensitive) {
for (var z = 0, t; t = ((typeof this[z] == "string" || typeof this[z] == "undefined") ? this[z] : this[z].name); z++) {
this[z] = new Array();
var x = 0, y = -1, n = 0, i, j;
while (i = (j = t.charAt(x++)).charCodeAt(0)) {
var m = (i == 46 || (i >= 48 && i <= 57));
if (m !== n) {
this[z][++y] = "";
n = m;
}
this[z][y] += j;
}
}
this.sort(function (a, b) {
for (var x = 0, aa, bb; (aa = a[x]) && (bb = b[x]); x++) {
if (caseInsensitive) {
aa = aa.toLowerCase();
bb = bb.toLowerCase();
}
if (aa !== bb) {
var c = Number(aa), d = Number(bb);
if (c == aa && d == bb) {
return c - d;
} else return (aa > bb) ? 1 : -1;
}
}
return a.length - b.length;
});
for (var z = 0; z < this.length; z++)
this[z] = this[z].join("");
}
但我从中返回的列表包含一个数组,其中只有 name
字段,没有相应的 id
。为什么会这样?
有没有办法应用这个算法来过滤对象?
我是 JavaScript 的新手,所以请保持温柔。
最佳答案
你可以使用 sorting with map和 String#localeCompare
带有选项
sensitivity
Which differences in the strings should lead to non-zero result values. Possible values are:
"base"
: Only strings that differ in base letters compare as unequal. Examples:a ≠ b
,a = á
,a = A
."accent"
: Only strings that differ in base letters or accents and other diacritic marks compare as unequal. Examples:a ≠ b
,a ≠ á
,a = A
."case"
: Only strings that differ in base letters or case compare as unequal. Examples:a ≠ b
,a = á
,a ≠ A
."variant"
: Strings that differ in base letters, accents and other diacritic marks, or case compare as unequal. Other differences may also be taken into consideration. Examples:a ≠ b
,a ≠ á
,a ≠ A
.The default is "variant" for usage "sort"; it's locale dependent for usage "search".
numeric
Whether numeric collation should be used, such that "1" < "2" < "10". Possible values are
true
andfalse
; the default isfalse
. This option can be set through an options property or through a Unicode extension key; if both are provided, theoptions
property takes precedence. Implementations are not required to support this property.
var array = ['Ex 10', 'Ex 2', 'a 10.1', 'a 1.1', 'a 10.0', 'a 2.0'];
array.sort((a, b) => a.localeCompare(b, undefined, { numeric: true, sensitivity: 'base' }));
console.log(array)
关于Javascript 自然排序对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52660451/