通过 PHP 生成时 Javascript 非法

Question

以下代码有效:

var r = confirm('Are you sure you want to delete this category?\nDeleting the category will leave child items without a category');

但是，当通过 php 生成相同的代码时，它会传递 Javascript Unexpected token ILLEGAL 错误...帮助？

echo "<script>var r = confirm('Are you sure you want to delete this category?\nDeleting the category will leave child items without a category');</script>";

是否可以在不使用ajax等的情况下做到这一点？我已经知道如何处理弹出窗口中的事件，只是在显示确认框时遇到一些问题。我可以只使用一个表单并获得预期的功能，但我认为确认框会更好。

Answer 1

您需要对新行进行两次转义，一次用于 JS，一次用于 PHP:

echo "<script>var r = confirm('Are you sure you want to delete this category?\\nDeleting the category will leave child items without a category');</script>";