我正在开发一个 Web 应用程序,我使用 jQuery 1.5 和 JavaScript 来实现该应用程序的主要功能。我从我的应用程序连接到 RESTful 界面,在其中获取某人的信息。 我使用这个函数从 json 页面检索信息:
var jqxhr = $.getJSON("example.json", function() { // store the data in a table }
我的 json 格式的数据是这样的,但结果我会得到不止一个人的格式:
[{"person":{"time":"2010-02-18T17:59:44","id":1,"name": "John","age":60, "updated_at":"010-02-18T17:59:44"}}]
如何在 JavaScript 表(更准确地说是数组)中仅存储此人的 id、姓名和年龄,而忽略其余信息?
最佳答案
这是您需要的基于 MAP 函数的特定 JavaScript/jQuery。
var originalData = [
{ "person": { "time": "2010-02-18T17:59:34", "id": 1, "name": "John", "age": 60, "updated_at": "010-02-18T17:59:41"} },
{ "person": { "time": "2010-02-18T17:59:44", "id": 2, "name": "Bob", "age": 50, "updated_at": "010-02-18T17:59:42"} },
{ "person": { "time": "2010-02-18T17:59:54", "id": 3, "name": "Sam", "age": 40, "updated_at": "010-02-18T17:59:43"} }
];
var data = $.map(originalData, function (ele) {
return { id: ele.person.id, name: ele.person.name, age: ele.person.age };
});
这是一个完整的示例,它将转换并以 HTML 形式显示结果。
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<link href="Styles/Site.css" rel="stylesheet" type="text/css" />
<script src="Scripts/jquery-1.6.1.js" type="text/javascript"></script>
<script type="text/javascript">
function CreateTableView(objArray, theme, enableHeader) {
// set optional theme parameter
if (theme === undefined) {
theme = 'mediumTable'; //default theme
}
if (enableHeader === undefined) {
enableHeader = true; //default enable headers
}
// If the returned data is an object do nothing, else try to parse
var array = typeof objArray != 'object' ? JSON.parse(objArray) : objArray;
var str = '<table class="' + theme + '">';
// table head
if (enableHeader) {
str += '<thead><tr>';
for (var index in array[0]) {
str += '<th scope="col">' + index + '</th>';
}
str += '</tr></thead>';
}
// table body
str += '<tbody>';
for (var i = 0; i < array.length; i++) {
str += (i % 2 == 0) ? '<tr class="alt">' : '<tr>';
for (var index in array[i]) {
str += '<td>' + array[i][index] + '</td>';
}
str += '</tr>';
}
str += '</tbody>'
str += '</table>';
return str;
}
$(document).ready(function () {
var originalData = [
{ "person": { "time": "2010-02-18T17:59:34", "id": 1, "name": "John", "age": 60, "updated_at": "010-02-18T17:59:41"} },
{ "person": { "time": "2010-02-18T17:59:44", "id": 2, "name": "Bob", "age": 50, "updated_at": "010-02-18T17:59:42"} },
{ "person": { "time": "2010-02-18T17:59:54", "id": 3, "name": "Sam", "age": 40, "updated_at": "010-02-18T17:59:43"} }
];
var data = $.map(originalData, function (ele) {
return { id: ele.person.id, name: ele.person.name, age: ele.person.age };
});
$('#results').append(CreateTableView(data, 'lightPro', true));
});
</script>
</head>
<body>
<div id="results" style="width: 500px; margin: 20px auto;">
</div>
关于javascript - 如何将 JSON 数据存储为 JavaScript 表格式?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6794967/