javascript - 验证数字数据 Javascript

Question

我正在用 Javascript 编写一个程序，将偶数和奇数分开，将它们放入一个数组，将数字的总和相加，然后求出平均值。

我遇到了一个问题，不允许零不计入。因为它添加到数组中，当用户输入 6+6 时，总和为 12，平均计算为 4，因为数组中额外的 0。

有什么办法不允许零计算吗？这是我到目前为止所拥有的..

var evenarray = [];
    var oddarray = [];
    var avgEven = 0;
    var avgOdd = 0;
    var isValid;
    function numberFunction(){

        do  
        {

            var numbers = prompt("Please enter numbers. Enter empty string to exit.");

            if(numbers % 2 == 0)
            {   
                    evenarray.push(numbers);
                    var sumEven = 0;
                        for (var i=0; i < evenarray.length; i++)
                        {
                            sumEven = sumEven + Number(evenarray[i]);
                        }
                    var avgEven = sumEven/evenarray.length;
                    //alert("even");

            }
            if(numbers % 2 !== 0)
            {
                    oddarray.push(numbers);
                    var sumOdd = 0;
                        for (var i=0; i < oddarray.length; i++)
                        {
                            sumOdd = sumOdd + Number(oddarray[i]);
                        }
                    var avgOdd = sumOdd/oddarray.length;
                    //alert("odd");
            }

            //if(isNaN(numbers)){

                //alert("Only numeric data only");
                //}
        }

        while(numbers !== "");

Answer 1

当数字实际为 0 时什么也不做:

if (numbers == 0)
{
}
else if(numbers % 2 == 0)
{   
  evenarray.push(numbers);
  var sumEven = 0;
  for (var i=0; i < evenarray.length; i++)
  {
    sumEven = sumEven + Number(evenarray[i]);
  }
  var avgEven = sumEven/evenarray.length;
}
else  // only odds remain
{
  oddarray.push(numbers);
  var sumOdd = 0;
  for (var i=0; i < oddarray.length; i++)
  {
    sumOdd = sumOdd + Number(oddarray[i]);
  }
  var avgOdd = sumOdd/oddarray.length;
}