我正在构建一个基于react redux的文件管理器webui(我的目的是通过这个项目掌握react和redux)
如您所知,文件管理器需要一个树浏览器。我想构建一个可以包含它自身并且每个都有自身状态的组件。如下所示:
TreeNode
也可以包含 TreeNode
的子节点。每个 TreeNode
都保持其状态 {path, children_nodes, right ... ..}
,children_nodes
是从server获取的,path
是parent传递的。这就是我的想象。
结构如下:
App:
TreeNode
--TreeNode
----TreeNode
----TreeNode
TreeNode
TreeNode
--TreeNode
TreeNode
--TreeNode
----TreeNode
----TreeNode
但是麻烦来了,因为 redux connect
存储到树根,根下的所有节点都接收相同的状态...
例如,我有一个OPEN_NODE
操作,它被设计为触发getFileList 函数
,基于该节点的路径并设置该节点的state.open
为true
。(注意:getFileList 函数
尚未实现,暂时提供假数据)
屏幕截图:
单击每个元素,但状态相同
。
我的代码:
容器/App.js
import React, { Component, PropTypes } from 'react';
import { bindActionCreators } from 'redux';
import { connect } from 'react-redux';
import Footer from '../components/Footer';
import TreeNode from '../containers/TreeNode';
import Home from '../containers/Home';
import * as NodeActions from '../actions/NodeActions'
export default class App extends Component {
componentWillMount() {
// this will update the nodes on state
this.props.actions.getNodes();
}
render() {
const { nodes } = this.props
console.log(nodes)
return (
<div className="main-app-container">
<Home />
<div className="main-app-nav">Simple Redux Boilerplate</div>
<div>
{nodes.map(node =>
<TreeNode key={node.name} info={node} actions={this.props.actions}/>
)}
</div>
{/*<Footer />*/}
</div>
);
}
}
function mapStateToProps(state) {
return {
nodes: state.opener.nodes,
open: state.opener.open
};
}
function mapDispatchToProps(dispatch) {
return {
actions: bindActionCreators(NodeActions, dispatch)
};
}
export default connect(
mapStateToProps,
mapDispatchToProps
)(App);
容器/TreeNode.js
import React, { Component, PropTypes } from 'react'
import { bindActionCreators } from 'redux'
import { connect } from 'react-redux'
import classNames from 'classnames/bind'
import * as NodeActions from '../actions/NodeActions'
export default class TreeNode extends Component {
constructor(props, context) {
super(props, context)
this.props = {
open: false,
nodes: [],
info:{}
}
}
handleClick() {
let {open} = this.props
if (open) {
this.props.actions.closeNode()
} else {
this.props.actions.openNode()
}
}
render() {
const { actions, nodes, info } = this.props
return (
<div className={classNames('tree-node', { 'open':this.props.open})} onClick={ () => {this.handleClick()} }>
<a>{info.name}</a>
{nodes &&
<div>{nodes.map(node => <TreeNode info={node} />)}</div>
}
{!nodes &&
<div>no children</div>
}
</div>
);
}
}
TreeNode.propTypes = {
open:PropTypes.bool,
info:PropTypes.object.isRequired,
nodes:PropTypes.array,
actions: PropTypes.object.isRequired
}
Action /NodeActions.js
import { OPEN_NODE, CLOSE_NODE, GET_NODES } from '../constants/NodeActionTypes';
export function openNode() {
return {
type: OPEN_NODE
};
}
export function closeNode() {
return {
type: CLOSE_NODE
};
}
export function getNodes() {
return {
type: GET_NODES
};
}
reducers/TreeNodeReducer.js
import { OPEN_NODE, CLOSE_NODE, GET_NODES } from '../constants/NodeActionTypes';
const initialState = {
open: false,
nodes: [],
info: {}
}
const testNodes = [
{name:'t1',type:'t1'},
{name:'t2',type:'t2'},
{name:'t3',type:'t3'},
]
function getFileList() {
return {
nodes: testNodes
}
}
export default function opener(state = initialState, action) {
switch (action.type) {
case OPEN_NODE:
var {nodes} = getFileList()
return {
...state,
open:true,
nodes:nodes
};
case CLOSE_NODE:
return {
...state,
open:false
};
case GET_NODES:
var {nodes} = getFileList()
return {
...state,
nodes:nodes
};
default:
return state;
}
}
完整代码见我的github https://github.com/eromoe/simple-redux-boilerplate
我没有看到涵盖此类组件的示例,谷歌搜索结果也没有任何帮助。 有什么办法可以克服这个问题吗?
更新: 我看到这个 How to manage state in a tree component in reactjs
但解决方案是将整棵树传递给状态,不能在文件管理器中使用。
最佳答案
我正在使用 React 和 Redux 实现类似 Github 的应用。
目前,我只列出存储库并显示其文件以及浏览它们。
我不知道这是好的还是坏的做法,但这就是我实现 Tree 组件的方式。
在每个树组件中,我都有一个指向自身的链接。我在路线上传递了一些数据,所以我能够在渲染它时获得下一棵树。
组件
class Tree extends Component {
constructor(props) {
super(props);
this.renderList = this.renderList.bind(this);
}
componentWillMount() {
this.props.getTree(this.props.params.sha);
}
componentWillReceiveProps(nextProps) {
if(nextProps.params.sha !== this.props.params.sha) {
this.props.getTree(nextProps.params.sha);
}
}
renderList(file) {
return (
<tr key={ file.sha }>
{ file.type == 'tree'
? <td><Link to={`/repository/${this.props.params.repoName}/tree/${file.path}/${file.sha}`}>{ file.path }</Link></td>
: <td><Link to={`/repository/${this.props.params.repoName}/blob/${file.sha}/${file.path}`}>{ file.path }</Link></td>}
</tr>
)
}
render() {
const treeFile = this.props.tree;
const fileName = this.props.params.path;
return (
<div className="row">
<h3>{ fileName }</h3>
<div className="col-md-12">
<table className="table table-hover table-bordered">
<tbody>
{ isEmpty(treeFile.tree) ? <tr>Loading</tr> : treeFile.tree.map(this.renderList) }
</tbody>
</table>
</div>
</div>
)
}
}
export default Tree;
Action
const setTree = (tree) => {
return {
type: actionTypes.GET_TREE,
tree
};
};
export const getTree = (sha) => {
return (dispatch, getState) => {
const { repository, profile } = getState();
const repo = GitHubApi.getRepo(profile.login, repository.name);
repo.getTree(sha, function(err, data) {
dispatch(setTree(data));
});
}
}
reducer
const initialState = "";
export const tree = (state = initialState, action) => {
switch (action.type) {
case actionTypes.GET_TREE:
return getTree(state, action);
}
return state;
}
const getTree = (state, action) => {
const { tree } = action;
return tree;
}
完整代码可以查看我在github上的仓库
关于javascript - 如何在 React Redux 中实现自包含组件?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37935756/