我有一个名为 ModalContainer 的文件,它根据 Prop 使用 switch 语句呈现子组件。
render() {
let visibleElement = null;
switch (this.props.modal) {
case constants.SEARCH_AND_HIGHLIGHT_MODAL:
visibleElement = <SearchAndHighlightModal/>;
break;
case constants.SAVE_SNIPPET_MODAL:
visibleElement = <SaveSnippetModal/>;
break;
case constants.SNIPPET_SAVED_MODAL:
visibleElement = <SnippetSavedModal/>;
break;
case constants.SAVE_SEARCH_MODAL:
visibleElement = <SaveSearchModal/>;
break;
default visibleElement = null;
我正在安装 ModalComponent 并传入 Prop ,但是当我尝试控制台记录输出时,我得到了 ReactWrapper {}
,我无法将其用于断言测试。
这是我的测试
import {expect} from 'chai';
import sinon from 'sinon';
import sinonTest from 'sinon-test';
import {Map} from 'immutable';
import React from 'react';
import {shallow, mount, configure} from 'enzyme';
import Adapter from 'enzyme-adapter-react-16';
import {mockStore} from '../test_helper';
//import {constants} from '../src/react/constants/constants.js';
import {ModalContainer} from '../../src/react/ModalContainer/ModalContainer';
configure({adapter: new Adapter()});
describe('Modal Container - Modal Container JSX', () => {
describe('Render from switch case', () => {
const fakeStore = mockStore(Map({}));
it('Render Search And Highlight Modal', () => {
const props = {
constants: {
SEARCH_AND_HIGHLIGHT_MODAL: 'search-and-highlight'
}
}
const wrapper = mount(<ModalContainer store={fakeStore}
visible={false}
modal={false}
metaData={null}
{...props}
/>);
//const visibleElement = wrapper.find();
//const myProps = wrapper.props();
console.log(wrapper.find('SearchAndHighlightModal'));
//expect(wrapper.find('SearchAndHighlightModal')).to.have.lengthOf(1);
});
});
});
我已经在单独的测试用例中测试了每个子组件,只需要测试文件的这一部分。 谢谢
最佳答案
要测试子组件是否正确呈现,您可以遵循下面给出的模式:
import {shallow} from "enzyme/build";
import ThemeProvider from "./mock-themeprovider";
import React from "react";
import ParentComponent from "./ParentComponent";
import ChildComponent from "./ChildComponent";
it("Does component renders child component correctly based on type?", () => {
const component = shallow(<ThemeProvider value="primary">
<ParentComponent
type={1} //for type 1 assuming it renders ChildComponent
/>
</ThemeProvider>);
console.log(component.debug());
const content = component.find(ParentComponent).dive().dive().find(ChildComponent);
expect(content.exists()).toEqual(true);
});
根据您对 ParentComponent 的实现,您可能需要执行多次 .dive()
甚至一次都不需要。
在浅层方法上编写测试用例 .debug()
时快速查看树可以节省大量时间!!!
关于javascript - 如何测试 React 组件是否已经从 switch 状态渲染?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56523841/