我有一个 list
$list = array('a','b','c','d','e','f');
$filter_list = join(", " $list);
select * from test where id_col=12 and try_col in ($filter_list);
谁能告诉我我该怎么做？
最佳答案
$list = array('a','b','c','d','e','f');
$filter_list = "'" . join("', '", $list) . "'";
$query = "select * from test where id=12 and try_col in ($filter_list)";
// select * from test where id=12 and try_col in ('a', 'b', 'c', 'd', 'e', 'f')
请注意，如果您的数组值包含 '，这将失败。这是一个解决方法:
$list = array("a'a",'a\a','b','c','d','e','f');
$temp = array_map("addslashes", $list);
$query = "SELECT * FROM test WHERE id=12 AND try_col in ('" . implode("','", $temp) . "')";
// SELECT * FROM test WHERE id=12 AND try_col in ('a\'a','a\\a','b','c','d','e','f')
关于php - SQL从数组中选择IN子句？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/7104051/