我有一个基于 CTE 的查询,我在其中检索两个给定时间跨度之间的每小时间隔。我的查询如下:
获取开始和结束日期时间(比如 07-13-2011 00:21:09 和 07-31-2011 21:11:21)获取每小时间隔之间的每小时总查询值(这里是从 00 到21,总共 21 小时,但这是参数化的,取决于我为输入提供的时间)每天。
此查询适用于第一个时间戳的小时数小于第二个时间戳的输入 - 例如第一个时间戳的时间是凌晨 03 点,第二个时间戳的时间是早上 07 点,但是有一个问题。当我想检索 07-13-2011 22:11:43 和 07-25-2011 04:06:04 等输入的查询总数时,我遇到了问题。我需要检索如下查询的总数:
07-13-2011 22:00:00 143 //representing the total amounts of queries 22:11:43 - 22:59:59 interval-
07-13-2011 23:00:00 121 //representing the total amounts of queries in 23:00:00 -23:59:59 interval-
07-14-2011 00:00:00 65 //00:00:00 - 00:59:59 interval
07-14-2011 01:00:00 51 //01:00:00 - 01:59:59 interval...
.
.
.
07-14-2011 04:00:00 22 //query amount for 04:00:00 - 04:06:04 interval
等等。除了我在下面编写的 CTE 查询之外,我还需要做什么?
WITH cal AS (
SELECT generate_series('2011-02-02 00:00:00'::timestamp
, '2012-04-01 05:00:00'::timestamp
, '1 hour'::interval) AS stamp
)
, qqq AS (
SELECT date_trunc('hour', calltime) AS stamp
, count(*) AS zcount
FROM mytable
WHERE calltime >= '07-13-2011 22:00:00'
AND calltime <='07-31-2011 04:33:21'
AND calltime::time >= '22:00:00'
AND calltime::time <= '04:33:21'
-- this calltime::time part obviously doesn't work due to common sense and logic
-- edited it to show what I try to mean
AND date_part('hour', calltime) >= 0
AND date_part('hour', calltime) <= 21
GROUP BY date_trunc('hour', calltime)
)
SELECT cal.stamp
, COALESCE (qqq.zcount, 0) AS zcount
FROM cal
LEFT JOIN qqq ON cal.stamp = qqq.stamp
WHERE cal.stamp >= '07-13-2011 22:00:00'
AND cal.stamp<='07-31-2011 04:33:21'
AND date_part('hour', cal.stamp) >= 0
AND date_part('hour', cal.stamp) <= 21
ORDER BY stamp ASC;
最佳答案
考虑这个修改后的版本:
WITH param AS (
SELECT '2011-07-13 22:11:43'::timestamp AS start -- supply start / stop once
,'2011-07-25 04:06:04'::timestamp AS stop
)
, cal AS (
SELECT generate_series(date_trunc('hour', p.start)
,date_trunc('hour', p.stop + interval '1h')
,interval '1h') AS h
FROM param p
)
, q AS (
SELECT date_trunc('hour', calltime) AS h
,count(*) AS ct
FROM mytable
,param p
WHERE calltime >= p.start
AND calltime <= p.stop
-- uncomment if you actually want to exclude hours 22 & 23 (?)
-- AND extract('hour' FROM calltime) BETWEEN 0 AND 21
GROUP BY 1
)
SELECT cal.h, COALESCE(q.ct, 0) AS ct
FROM cal
LEFT JOIN q USING (h)
-- uncomment if you actually want to exclude hours 22 & 23 (?)
-- WHERE extract('hour' FROM cal.h) BETWEEN 0 AND 21
ORDER BY 1;
主要变化是立即根据实际时间跨度生成小时数。
删除了几个不需要的条件。
对时间戳使用 ISO 8601 格式(适用于所有语言环境)。
在此 related answer 中查找更多上下文和链接.唯一的区别是:那边是关于正在运行的计数。
关于sql - 当时间戳开始时间大于时间戳结束时间时查询失败,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11967396/