java - 用截击发送对象

标签 java android node.js postgresql android-volley

我有一个疑问让我感到困惑,我正在使用 android/nodejs/postgreSQL, 我能够向服务器发送 http 请求并存储信息。

但我这样做时没有考虑好的做法,即让模型与用户相关联。

所以基本上我从注册表单中获取数据,使用表单信息执行简单的 params.put 并发送带有键/值信息的数据。

但现在我想要一个用户模型并通过 params.put 传递用户模型并做同样的事情。

这是一种好的做法吗?还是我应该忘记 User 模型并做这样的事情?

这是我目前正在做的事情:

 public void register(View view) {

        //get form data
        final String username = usernameTxt.getText().toString();
        String password = passwordTxt.getText().toString();
        String email = emailTxt.getText().toString();
        Log.d("email",String.valueOf(isValidEmail(email)));

        if (!isValidEmail(email)) {
            emailTxt.setError("Invalid Email");
        }

        //inicialize a map with pair key value
        final Map<String, String> params = new HashMap<String, String>();

        // Add form fields to the map
        params.put("username", username);
        params.put("email", email);
        params.put("password", password);

        /**
         * Efetua um pedido ao servidor
         *
         * @param URl    url do servidor a aceder
         * @param JSONObject objeto json a ser retornado através do access point
         *
         */
        JsonObjectRequest request = new JsonObjectRequest(URL, new JSONObject(params),
                new Response.Listener<JSONObject>() {
                    @Override
                    public void onResponse(JSONObject response) {
                        //TODO verificar o status code da resposta apenas deverá registar login caso seja 200
                        //verifica
                        Log.d("response",response.toString());
                        Intent i = new Intent(Register.this,Login.class);
                        i.putExtra("username",username);
                        startActivity(i);
                        finish();
                    }
                }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {
                String body;
                //get response body and parse with appropriate encoding
                if(error.networkResponse.data!=null) {
                    String statusCode = String.valueOf(error.networkResponse.statusCode);
                    try {
                        body = new String(error.networkResponse.data,"UTF-8");
                        JSONObject jsonObj = new JSONObject(body);
                        Log.d("body",String.valueOf(jsonObj.get("message")));
                        showToast(String.valueOf(jsonObj.get("message")));
                    } catch (UnsupportedEncodingException e) {
                        showToast("You need to connect to the internet!");
                    } catch (JSONException e) {
                        Log.d("json:","problems decoding jsonObj");
                    }
                }
                //do stuff with the body...
            }


        });

        request.setRetryPolicy(new DefaultRetryPolicy(60000, DefaultRetryPolicy.DEFAULT_MAX_RETRIES, DefaultRetryPolicy.DEFAULT_BACKOFF_MULT));

queue.add(request);
}

最佳答案

希望对您有所帮助,尝试在您的应用程序中实现

public class MainActivity extends AppCompatActivity implements View.OnClickListener {

    private static final String REGISTER_URL = "http://foo.com/UserRegistration/volleyRegister.php";

    public static final String KEY_USERNAME = "username";
    public static final String KEY_PASSWORD = "password";
    public static final String KEY_EMAIL = "email";


    private EditText editTextUsername;
    private EditText editTextEmail;
    private EditText editTextPassword;

    private Button buttonRegister;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        editTextUsername = (EditText) findViewById(R.id.editTextUsername);
        editTextPassword = (EditText) findViewById(R.id.editTextPassword);
        editTextEmail= (EditText) findViewById(R.id.editTextEmail);

        buttonRegister = (Button) findViewById(R.id.buttonRegister);

        buttonRegister.setOnClickListener(this);
    }

    private void registerUser(){
        final String username = editTextUsername.getText().toString().trim();
        final String password = editTextPassword.getText().toString().trim();
        final String email = editTextEmail.getText().toString().trim();

        StringRequest stringRequest = new StringRequest(Request.Method.POST, REGISTER_URL,
                new Response.Listener<String>() {
                    @Override
                    public void onResponse(String response) {
                        Toast.makeText(MainActivity.this,response,Toast.LENGTH_LONG).show();
                    }
                },
                new Response.ErrorListener() {
                    @Override
                    public void onErrorResponse(VolleyError error) {
                        Toast.makeText(MainActivity.this,error.toString(),Toast.LENGTH_LONG).show();
                    }
                }){
            @Override
            protected Map<String,String> getParams(){
                Map<String,String> params = new HashMap<String, String>();
                params.put(KEY_USERNAME,username);
                params.put(KEY_PASSWORD,password);
                params.put(KEY_EMAIL, email);
                return params;
            }

        };



           RequestQueue requestQueue = Volley.newRequestQueue(this);
            requestQueue.add(stringRequest);
        }

        @Override
        public void onClick(View v) {
            if(v == buttonRegister){
                registerUser();
            }
        }
    }

关于java - 用截击发送对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44068202/

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