因此,我有以下架构 build_tasks:
id|building|queue_time|start_time|completion_time|status|createdAt|updatedAt|baseId|
我试图只获取状态为“待定”的构建任务,其中没有处于“进行中”状态的具有相同 baseId 的构建任务。
到目前为止,我设法获得了一个表,其中包含所有待处理的构建任务,其中没有正在进行的构建任务。这是查询:
select * from (select build_tasks.* from build_tasks
where status = 'pending') as p
left join in_progress_build_tasks ipbt on p."baseId" = ipbt."baseId"
where ipbt."baseId" is null;
其中 in_progress_build_tasks 是 View :
CREATE OR REPLACE VIEW "public".in_progress_build_tasks AS
SELECT DISTINCT build_tasks."baseId"
FROM build_tasks
WHERE build_tasks.status = 'in-progress'::enum_build_tasks_status;
哪个用于表:
id |building |queue_time |start_time |completion_time |status |createdAt |updatedAt |baseId |
---|--------------------|--------------------|--------------------|--------------------|------------|--------------------|--------------------|-------|
7 |resource01_refinery |2018-02-04 14:09:49 | | |pending |2018-02-04 14:09:49 |2018-02-04 14:09:49 |1 |
10 |resource01_refinery |2018-02-04 14:45:07 | | |pending |2018-02-04 14:45:07 |2018-02-04 14:45:07 |1 |
6 |resource01_refinery |2018-02-04 14:07:32 |2018-02-04 14:07:58 |2018-02-04 14:08:08 |in-progress |2018-02-04 14:07:32 |2018-02-04 14:08:09 |1 |
12 |resource01_refinery |2018-02-04 14:46:04 |2018-02-04 14:46:04 |2018-02-04 14:46:04 |successful |2018-02-04 14:46:04 |2018-02-04 14:58:28 |2 |
8 |resource01_refinery |2018-02-04 14:10:29 |2018-02-04 14:10:29 |2018-02-04 14:10:39 |successful |2018-02-04 14:10:29 |2018-02-04 14:10:39 |2 |
9 |resource01_refinery |2018-02-04 14:11:38 | | |pending |2018-02-04 14:11:38 |2018-02-04 14:11:38 |2 |
11 |resource01_refinery |2018-02-04 14:45:14 | | |pending |2018-02-04 14:45:14 |2018-02-04 14:45:14 |2 |
13 |resource01_refinery |2018-02-04 15:11:16 | | |pending |2018-02-04 15:11:16 |2018-02-04 15:11:16 |3 |
15 |resource01_refinery |2018-02-04 15:11:19 | | |pending |2018-02-04 15:11:19 |2018-02-04 15:11:19 |3 |
14 |resource01_refinery |2018-02-04 15:11:18 | | |pending |2018-02-04 15:11:18 |2018-02-04 15:11:18 |3 |
给我输出:
id |building |queue_time |start_time |completion_time |status |createdAt |updatedAt |baseId |baseId |
---|--------------------|--------------------|-----------|----------------|--------|--------------------|--------------------|-------|-------|
9 |resource01_refinery |2018-02-04 14:11:38 | | |pending |2018-02-04 14:11:38 |2018-02-04 14:11:38 |2 | |
11 |resource01_refinery |2018-02-04 14:45:14 | | |pending |2018-02-04 14:45:14 |2018-02-04 14:45:14 |2 | |
13 |resource01_refinery |2018-02-04 15:11:16 | | |pending |2018-02-04 15:11:16 |2018-02-04 15:11:16 |3 | |
14 |resource01_refinery |2018-02-04 15:11:18 | | |pending |2018-02-04 15:11:18 |2018-02-04 15:11:18 |3 | |
15 |resource01_refinery |2018-02-04 15:11:19 | | |pending |2018-02-04 15:11:19 |2018-02-04 15:11:19 |3 | |
如何将结果减少到每个 base_id 只有 1 行,根据最低的 queue_time 选择?
最佳答案
我不清楚你想要输出什么。但是如果你想找出满足你条件的base ids,你可以使用聚合:
select bt.baseid
from build_tasks bt
group by bt.baseid
having sum( (bt.status = 'pending'::enum_build_tasks_status)::int) > 0 and
sum( (bt.status = 'in-progress'::enum_build_tasks_status)::int) = 0 ;
我不确定你还想要什么输出。您可能可以使用聚合获得想要的东西。或者,join
、in
或 exists
可以获得您想要的。
但是,您不需要 View 来完成您正在做的事情。
关于sql - 如何在 SQL 中每列值只选择一行?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48609130/