当我尝试使用 Hibernate 创建任何数据库查询时, 我犯了同样的错误: Error code
道法:
@Override
public List findAll() {
openCurrentSessionWithTransaction();
List books = currentSession.createQuery("from AuthorEntity").list();
closeCurrentSessionWithTransaction();
return books;
}
AuthorEntity(Setter 和 hashcode&equals 存在但隐藏):
import javax.persistence.*;
import java.util.Objects;
@Entity
@Table(name = "author")
public class AuthorEntity {
private long authorId;
private String name;
@Id
@Column(name = "author_id")
public long getAuthorId() {
return authorId;
}
@Basic
@Column(name = "name")
public String getName() {
return name;
}
}
为什么会出现这个错误?我在 IntellijIdea 2018,Java 1.8 上执行此操作。 hibernate.cfg.xml
最佳答案
你能为你的 sessionFactory 尝试这段代码吗?它帮助了我
final StandardServiceRegistry registry = new StandardServiceRegistryBuilder()
.configure().build();
sessionFactory = new MetadataSources(registry).buildMetadata().buildSessionFactory();
关于java - Hibernate QuerySyntaxException 表未映射,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53282122/