sql - 在单个查询中从两个不同的条件获取不同的值

Question

我需要得到如下结果

section_one | section_two
56788              678

这是我写的分别有上述结果的查询

Select count(*) as section_one from tableNew
WHERE columnone LIKE %hjk%

和

Select count(*) as section_two from tableNew
WHERE columnone NOT LIKE %hjk%;

如何将这两个组合在一个查询中并获得如上所示的结果？

我尝试了下面的方法，但似乎无法正常工作

select *,
CASE
WHEN columnone LIKE %hjk% THEN count(1) as section_one
ELSE count(1) as section_two
END
from tableNew
Group by tableid;

有没有其他方法可以在一个查询中同时拥有这两个条件？ 在这方面的任何帮助都会很棒!

P.S: 还有其他方法可以检查 boolean 条件，而不是 columnone LIKE %hjk% 目标 columnone 不为空

Answer 1

尝试使用 SUM

select 
SUM(columnone LIKE %hjk%)  as section_one,
SUM(columnone NOT LIKE %hjk%)  as section_two
from tableNew
Group by tableid;

或者你可以使用CASE

select 
SUM(CASE WHEN columnone LIKE %hjk% THEN 1 ELSE 0 END)  as section_one,
SUM(CASE WHEN columnone NOT LIKE %hjk% THEN 1 ELSE 0 END)  as section_two
from tableNew
Group by tableid;