我有一个 (Postgres
) 查询,其中包含一个常用的 group by
子句:
select extract(year from a.created) as Year,a.testscoreid, b.irt_tlevel, count(a.*) as Questions
from asmt.testscores a join asmt.questions b
on a.questionid = b.questionid
where a.answered = True
group by Year,a.testscoreid, b.irt_tlevel
order by Year desc, a.testscoreid
b.irt_tlevel
列的值为 low
、medium
和 high
,所有这些结果都在一个行格式,例如:
Year TestScoreId Irt_tlevel Questions
2015 1 Low 2
2015 1 Medium 3
2015 1 High 5
我希望我的结果采用以下格式:
Year TestScoreId Low Medium High TotalQuestions
2015 1 2 3 5 10
如有任何帮助,我们将不胜感激。
最佳答案
如果已知 irt_tlevel 列中不同值的数量是固定的,则可以使用条件聚合。
select
extract(year from a.created) as Year,
a.testscoreid,
sum(case when b.irt_tlevel = 'Low' then 1 else 0 end) as Low,
sum(case when b.irt_tlevel = 'Medium' then 1 else 0 end) as Medium,
sum(case when b.irt_tlevel = 'High' then 1 else 0 end) as High,
count(*) as Questions
from asmt.testscores a
join asmt.questions b on a.questionid = b.questionid
where a.answered = True
group by Year, a.testscoreid
order by Year desc, a.testscoreid
关于sql - 使 `group by` 导致多列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34500598/