sql - Symfony2 Orderby特定字段值优先

Question

Symfony2 当 Case 不工作时。

想先按特定字段值排序

$query->select('s.firstName as first_name,s.lastName as last_name,sts.name as status_name')
            ->leftJoin('s.studentStatus', 'sts')
            ->where($query->expr()->orx(
                $query->expr()->like('s.internalId', ':internalId'),
            ))
            ->addSelect('(CASE WHEN s.storeID = :location THEN 1 else 2) AS HIDDEN storeOrder')
            ->setParameter('internalId', "%{$internalId}")
            ->setParameter('location', "{$location}")
            ->orderBy('storeOrder', 'ASC')
            ->setMaxResults((int) $limit);

想要先按列的特定值排序，其他值在其后。我有 SQL 查询，但它不能使用以下语法

Answer 1

您可以添加一个隐藏字段 storeOrder 然后按此字段排序:

$query->select('s.firstName as first_name,s.lastName as last_name,sts.name as status_name')
           ->leftJoin('s.studentStatus', 'sts')
            ->where($query->expr()->orx(
                $query->expr()->like('s.internalId', ':internalId'),
            ))
            ->addSelect('(CASE WHEN s.storeID = :location THEN 1 else 2) AS HIDDEN storeOrder')
            ->setParameter('name', "%{$term}%")
            ->setParameter('internalId', "%{$internalId}")
            ->setParameter('location', "{$location}")
            ->orderBy('storeOrder', 'ASC')
            ->setMaxResults((int) $limit);