我正在编写一个用作数据库 View 的查询,它现在看起来像这样:
SELECT
contact.*,
contact_users.names AS user_names,
contact_status.status_id AS status_id,
status_translation.name AS status_name,
status_translation.lang_id AS lang_id
FROM contacts as contact
LEFT JOIN contact_status AS contact_status ON contact_status.status_id = contact.status
LEFT JOIN contact_status_translation AS status_translation ON status_translation.id = contact.status
LEFT JOIN (
SELECT
contacts_users.contact_id,
string_agg(users.fullname || ', ' || users.id, ' | ') as names
FROM v_contacts_users as contacts_users
LEFT JOIN v_users as users on users.id = contacts_users.user_id
WHERE users.lang_id = status_translation.lang_id
GROUP BY contacts_users.contact_id
) AS contact_users ON contact_users.contact_id = contact.id
WHERE contact.deleted = FALSE
除最后一个 LEFT JOIN
中的 WHERE
条件外,一切都按预期工作 - WHERE users.lang_id = status_translation.lang_id
部分表示status_translation
无法在这部分查询中引用?这是为什么?我尝试用各种方式引用此表,但结果仍然相同。v_users
也已翻译,因此我只需要从该表中获得一个结果。
最佳答案
如果您想引用以前的 FROM
列表条目,请在 LEFT JOIN
和左括号之间插入 LATERAL
。
关于SQL在子查询中使用来自join的表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44135088/